Can someone help pls, what is wrong...

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The convertCelsiusToFahrenheit(int celsius) method accepts a value in degrees Celsius. The method should convert the temperature and return the value in degrees Fahrenheit.
The Celsius temperature (TC) and the Fahrenheit temperature (TF) are related by the following relationship:
TF = (9 / 5) * TC + 32.

Consider this example:
A value of 41 is passed to the convertCelsiusToFahrenheit method.

Example output:
105.8

Requirements:

The convertCelsiusToFahrenheit(int) method must be public and static.
The convertCelsiusToFahrenheit method must return a double.
The convertCelsiusToFahrenheit method should not display anything.
The convertCelsiusToFahrenheit method must correctly convert degrees Celsius to degrees Fahrenheit and return the result.

package com.codegym.task.task01.task0130; /* Our first converter! */ public class Solution { public static void main(String[] args) { System.out.println(convertCelsiusToFahrenheit(41)); } public static double convertCelsiusToFahrenheit(int celsius) { double fahrenheit = (41 * 1.8) + 32; return fahrenheit; } }

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Aaron

Level 2 , Germantown, United States

6 December 2018, 15:55

Why is it + 32 when the formula is - 32

Aswini

Level 4 , Chennai, India

13 November 2018, 07:20

public class Solution { public static void main(String[] args) { System.out.println(convertCelsiusToFahrenheit(41)); } public static double convertCelsiusToFahrenheit(int celsius) { //write your code here double fahrenheit = 9 / 5.0 * celsius + 32; return fahrenheit; } }

-2

Krishna shahi

Level 3 , Uttarakhand, India

4 November 2018, 11:39

May this will help you- public class Solution { public static void main(String[] args) { System.out.println(convertCelsiusToFahrenheit(41)); } public static double convertCelsiusToFahrenheit(int celsius) { double TF=(double)((celsius)*9.0/5.0)+ 32; return TF; } }

Ana Georgievska

Level 2 , Skopje, Macedonia, The Former Yugoslav Republic of

4 November 2018, 23:49

It works.Thanks

Krishna shahi

Level 3 , Uttarakhand, India

5 November 2018, 14:04

Always welcome dear . For further help you can DM me. And please press '+' sign in my first comment.

Ashish RajAnand

Level 13 , Bhilai , India

6 November 2018, 05:06

Here I mention that 9/5 is always gives only integer data i.e. 1 not 1.8 Only you need to convert it 9/5 integer data type to double data type i.e. 9 / 5 = 1 9.0 / 5 = 1.8 9 / 5.0 = 1.8 9.0 / 5.0 = 1.8 for example celsius*9.0/5+32 celsius*9/5.0+32 celsius*9.0/5.0+32 This is basic concept . one more thing you can convert int celsius to double by using (double)celsius