i cant do it after many tries

Question about the task

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codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { int min; if (a <= b, a<= c, a<= d) min= a; else if (b <= a, b<= c, b<= d) min = b; else if (c <= a, c<= b, c<= d) min = c; else min = d; return min(a, b); } public static int min(int a, int b) { int min; if (a <= b) min = a; else min = b; return min; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

Write a function that computes the minimum of four numbers.
The function min(a, b, c, d) should use (call) the function min(a, b)

Hint:
You need to write the body of the two existing min functions.

Requirements:

The program should display text on the screen.
The min methods should not display text on the screen.
The main method should call min(a, b) and min(a, b, c, d).
The main method should display the result of the min methods. Each time, on a new line.
The min(a, b) method must return the minimum of the numbers a and b.
The min(a, b, c, d) method must use the min(a, b) method.
The min(a, b, c, d) method must return the minimum of the numbers a, b, c, and d.

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { int min; if (a <= b, a<= c, a<= d) min= a; else if (b <= a, b<= c, b<= d) min = b; else if (c <= a, c<= b, c<= d) min = c; else min = d; return min(a, b); } public static int min(int a, int b) { int min; if (a <= b) min = a; else min = b; return min; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

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Андрій Білусяк

Level 4 , Ivano-Frankivsk, Ukraine

14 May 2020, 12:16

You need to call the min method with arguments a, b. in the method of mines with arguments a, b, c, d,. Compare them with each other, and return the result of the smaller value of the method.

Onome Brownly-Otiede

Level 9 , Galway, Ireland

13 May 2020, 18:09

Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { int min; if (a <= b && a <= c && a <= d) min = a; else if (b <= a && b <= c && b <= d) min = b; else if (c <= a && c <= b && c <= d) min = c; else min = d; return min; } public static int min(int a, int b) { int min; if (a <= b) min = a; else min = b; return min; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

Thomas

Level 41 , Bayreuth, Germany

12 May 2020, 20:14

(a <= b, a<= c, a<= d) Java doesn't know such a syntax, the commas. Something like that would work

if (a <= b && a <= c && a <= d) {