Please help

import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader bf = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(bf.readLine()); int b = Integer.parseInt(bf.readLine()); int c = Integer.parseInt(bf.readLine()); if(a == b && a != c){ System.out.println(3); }else if(b==c && b!=a){ System.out.println(1); }else if(c == a && c!=b){ System.out.println(2); } } }

//the simplest solution is here BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(br.readLine()); int b = Integer.parseInt(br.readLine()); int c = Integer.parseInt(br.readLine()); // first we check that if any two //numbers are equal, then we proceed if(a ==b || b ==c || a==c) { if (a != b && a != c) System.out.print("1"); else if(b != a && b != c) System.out.print("2"); else if(c != a && c != b) System.out.print("3"); }

line 24 output should be 3. because you test that if a which is in position 1 is equals to b which is in position 2 and if a is not equal to c then the index of the number that is not identical is 3 because index 1 equals to index 2 the only position left is 3. it's safe to start counting from 1, not 0. Add 1 to all your outputs. for example if(a == b && b != c){ System.out.println(3); }else if(a == c && b != c){ System.out.println(2); }else if(b==c && a != b){ System.out.println(1);

You can Try This, Its work for me..... if (num1!=num2 && num1!=num3 && num2==num3 ) { System.out.println("1"); } if (num2!=num1 && num2!=num3 && num1==num3 ) { System.out.println("2"); } if (num3!=num1 && num3!=num2 && num1==num2 ) { System.out.println("3"); }

b = c (1) a = b (3) a = c (2) try using this logic :>

Now it's working :) Thanks

The problem seems to be the index numbers. Try 1,2,3 instead of 0,1,2. I hope this helps!