Dlaczego pojawią się kwadrat m*m?

Pytania dotyczące zadania

Rysowanie prostokąta

Składnia Java, Poziom 4, Lekcja 13

Dyskutowane

Czemu pętla, która powinna wykorzystać n nie działa jak powinna?

package pl.codegym.task.task04.task0436; /* Rysowanie prostokąta */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //tutaj wpisz swój kod BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int m = Integer.parseInt(reader.readLine()); int n = Integer.parseInt(reader.readLine()); for (int j = 0; j<=m; j++) { for (int i = 0; i <= n; i++) { if (i < n) { System.out.print("8"); } else { System.out.println("8"); } } } } }

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Norbert

Poziom 41

5 lutego 2023, 07:12

przydatny

BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
int a = Integer.parseInt(reader.readLine());
int b = Integer.parseInt(reader.readLine());

for(int i = 1; i <= a; i++){
   for(int j = 1; j <= b; j++){
       System.out.print("8");
   }
    System.out.println();
}

Magda

Poziom 10 , Poland, Poland

4 stycznia 2023, 09:08

Thanks very much :)

Thomas

Poziom 41 , Bayreuth, Germany

4 stycznia 2023, 08:31

przydatny

neither loop works as expected... if you want to go over 4 iterations and you count from 0 to <= 4, then it is 5 iterations: 0, 1, 2, 3 and 4. So usually (except you have a very good reason) you start loops at 0 and the condition just uses a <

for (int i = 0; i < m; i++) { /* now you have exactly m iterations */ }

Your inner loop is doing the same, it iterates n + 1 times. The condition inside that inner loop takes care of the first n times to print a 8, and the last time it prints a 8\n. That's not really what you want ;) I suggest to have a (outer) loop iterating m times and just printing a \n, like

for (int y = 0; y < m; y++) {
    System.out.println();
}

Now you have m rows. You just need to add an inner loop that prints n cells (without linebreaks). Place that loop right before the outer sout and you're done. It is pretty much the same as in your last question, the matrix printed using while loops

int
        y = 0,
        x = 0;

while (y++ < 10) {
    while (x++ < 10)
        System.out.format("%3s ", y * x);
    System.out.println();
    x = 0;
}