How to initialize variable m

W metodzie min( int a, int b, int c, int d) trzeba porównać 3 wartości min ( int a i int b) , c oraz d Jest to odnisienie do poprzedniego zadania. int m = 0; if (min(a,b) <= c && min(a,b) <= d) m = min(a,b); else if (c <= min(a,b) && c <= d) m = c; else if (d <= min(a,b) && d <= c) m = d; return m;

inicialize m int m = 0;

I think your confusion lies in the fact that a block of code does not share variables. So, one block of code is this:

public static int min(int a, int b) { // variables a and b declared
   int m; // variable m declared
   if(a<b)
      m=a;
   else
      m=b;
   return m;
}

Here you have variables a, b, and m. Then in this block of code:

public static int min(int a, int b, int c, int d){ // a, b, c, d declared
   int m2; // m2 declared
   int m; // m declared
   if(m<c&&m<d) // m is being used here but has no value
      m2=m;
   else if(c<m&&c<d)
      m2=c;
   else
      m2=d;
   return m2;
}

You have 6 different variables that only exist in this block of code. They are a, b ,c ,d , m2, and m. These variables are specific to this block of code only and have no access to other blocks of codes, like the one above, even though a, b, and m have the same names as the other block. It is like having 2 people with the same name, they have the same name but are completely different people.

package pl.codegym.task.task02.task0217; /* Najmniejsza z czterech liczb */ public class Solution { public static int min(int a, int b, int c, int d) { int m2; if (min(a,b)<=c && min(a,b)<=d) m2 = min(a,b); else m2 = d; return m2; } public static int min(int a, int b) { int m1; if(a<b) m1 = a; else m1= b; return m1; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

Cześć. 1. Masz sprawić tak że program wybierać będzie najmniejszą z a , b, c , d, więc nie bardzo rozumiem po co tam "m". Kiedy już napiszesz ciało tych dwóch funkcji trzeba by pierwsza odwołała się do drugiej i powinno wyjść.