Minimum of four numbers

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Yusuf, please create a question regarding this task in HELP section and send us a link. Our devs will be happy to assist you with the task.

Create an object for your function. Int e= min(a,b); Then search for the smallest value And when your stuck check out the Community help functie.

for example, you need to use the perimeterOfSquare method, which should calculate the perimeter of a square. Correct version:

public class Solution {
    public static void main(String[] args) {
        int perimeter = perimeterOfSquare(2);
        System.out.println(perimeter);
    }

    public static int perimeterOfSquare(int side) {
        return 4 * side;
    }
}

Wrong version:

public class Solution {
    public static void main(String[] args) {
        int perimeter = perimeterOfSquare(2);
        System.out.println(4*2);
    }

    public static int perimeterOfSquare(int side) {
        return 4 * side;
    }
}

Output is the same, but ...

Please post your question with the attached solution in the section Help.

Because tests use different data

Start with the second min function. The second function will return to you the min which is a or b and will print when it's called in the main function. For the first min, you need to call the second function to do the same thing for int a and b. You can do that by typing:

int whatever = min(a, b); \\ whatever is a variable, name it anything.

now "whatever" is the min of int a and int b. Now, use it to get the min of the three variables, "whatever", c and d. Then, let the function return to you the smallest of these and you're done.