Number of days in the year

It can be solved without the operator % hint: when int a can be evenly divisible by int b, a==(a/b)*b.Then you can nail it with if/else!

Number of days in the year: x , where x is 366 for a leap year, and x is 365 for an ordinary year. all this means is they want you to hard-code the numbers in! I was putting a variable x and x++, thus failing the test over and over again! what a STUPID waste of time! :/

I created code to perform all the functions, however, I was leaving off the #4 task. The line of code that covered "all the remaining years"

For some reason, the help section won't accept my question. Can anyone help me out here? The third requirement is not met. package com.codegym.task.task04.task0414; /* Number of days in the year */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in)); String y = bufferedReader.readLine(); int a = Integer.parseInt(y); int leap400 = a % 400; int nonLeap = a % 100; int leap4 = a % 4; if (a == leap400) { System.out.println("Number of days in the year: 366"); } else if (a == nonLeap) { System.out.println("Number of days in the year: 365"); } else if (a == leap4) { System.out.println("Number of days in the year: 366"); } else { System.out.println("Number of days in the year: 365"); } } }

Third requirement not met. They don't allow me to post my question in the help section. It says "Invalid request argument"

// I skipped the task with frustration and returned with ease after learning "%"

I did waste 13 tries to get tis right.

Every year that is evenly divisible by 4 is a leap year, unless they are evenly divisible by 100, in which case they also need to be evenly divisible by 400.

This Statement "if the year is evenly divisible by 400, then it is a leap year" is false coz 2004 / 400 = 5.01

follow the steps from the hint it is very helpful.e.g. 4 steps then use 4 if else statements.