If you think all cats are cute fur balls, you probably haven't encountered alley cats in a heated struggle for supremacy in a certain area. It's time for you to meet them. More precisely, it's time to simulate a decisive battle between the three most powerful cats in the neighborhood. For combat, we will use the boolean fight(Cat anotherCat) method.
Feline carnage
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Joe M
6 October 2020, 18:26
OK...learning
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Syed Huzaifa
9 May 2020, 20:50
create there objects of Cat class
call the method of fight on each object and pass the other cat object
and try to display the result that could be done in number of ways u've to think +1
smortne
25 January 2020, 19:20
If you changed the code in line 38 from "score > 2" to "score > 1" it might please some furious losing cats...
+3
Brandon Nicolle
23 August 2019, 03:15
Can somebody tell me what lesson they taught how to use (Cat anotherCat) as obj1.fight(obj2). I was trying to use it as :
System.out.println(fight(obj1, obj2));
But that didn't work.
+1
Brandon Leirer
2 June 2020, 20:49
This wasn't really explained anywhere that I have seen. There is a place that says when using the dot operator the object attached to it is set as the first argument. So, cat1.fight() would call the fight method and assign cat1 object as the first argument. cat1.fight(cat2) would set cat2 two as the second argument.
But I agree with you, writing (Cat anotherCat) is confusing. I'm still not 100% sure how that is supposed to indicate that only one cat object goes in there.
+1
Param M
26 June 2019, 04:19
guys all you need to do is this
in the main method. Do not touch the default setting of theirs +1
Roman
26 June 2019, 05:53
Posting the solution in the comments is prohibited.
+3
Jaisingh
15 September 2018, 14:40
How should i deal with the static class, i have studied that static variable and static methods are accessed without creating object, shell we create object of static Class, and we apply this operator for static variable or static methods it is by default is null. so what will be for the static class, so please help me quick
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Roman
17 September 2018, 05:22
If you need help, something isn't right in your code, the server won't accept your solution (even if you are 100% sure that it is correct). Describe your question/issue in the HELP section at codegym.cc/help.
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