R or L

The statement is not well explained and I do not understand the solution because it does not explain why it does one thing or another.

Hint: don't (int i = 0; i < list.size(); i++), do (int i = size() - 1; i >= 0 ; i++) If you're here it means you know that you are stuck on the part regarding removal.

This is simple one: 1. declare two lists, one to add all the removed elements and one for adding all the duplicating elements. populate these two lists using loop. 2. from the original list remove one list and add other list. simple.

This task requirement is to solve without using keyboard, but the solution read data from keyboard.

Here is a great link to help you understand how to search characters in a string, helped me out a ton: https://www.geeksforgeeks.org/searching-for-character-and-substring-in-a-string/ I'm sure you can compile a satisfactory solution after reading & understanding character functions.

the most difficult/important part of the solution is using extra i++ and i-- once. Took a while to understand why these were necessary, but it's important b/c the logic fails without them, never mind the checker.

Hardest exercise so far. I spent 6 hours on this and had to get help to be able to resolve it. Still don't really understand why. Feels disappointing.

Oh man this is tough to understand....I downloaded solution :(. Thanks to all who triedit. I looked at your tries and learned something.

I think there is a problem of explanation of this exercise, should be rectified from the admin ... how can be the point 2.1 before 2.3??? if you remove all the words with containing "r" at the point 2.1 how does the point 2.3 be fulfilled??? so the paragraph 2.3 should be 2.1 :) ....

A hint how I did it: 1. For a fix method use "for loop" (int i = 0; i < list.size();) to iterate through the list, but don't specify the 3rd argument (i++). 2. Inside the loop use 3 if / else if statements: 2.1. if ((string contains "r" AND "l") OR (doesn't contain "r" AND "l) proceed iteration (i++); 2.2. else if a string contains "r" use .remove but don't iterate further (leave i unchanged); 2.3. else if a string contains "l" use .add to duplicate the string, but make sure to place at exact index iteration is at ( .add(i, list.get(i)) ). Iterate further 2 steps (i+= 2); 3. And lastly don't forget to change return statement so it returns the list, not null. I hope it helps. Good Luck!