1. Figure out how the program works. 2. Without changing the T1 and T2 classes, make it so their threads finish (not necessarily successfully). 3. Don't use the sleep method.
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12 February 2022, 10:06
The code below allows both threads to finish (and is accepted as a solution to this task) - could anyone please help me understand why? Is t2.join() in T1 immediately satisfied because t2 was not yet started? If so, then I avoided the deadlock by making the threads work sequentially...which shouldn't be really accepted as a correct solution, I think. But I'm just guessing here :)