Most frequent bytes

Weird solution. You should've used Map.

Why in correct solution they decided to create array with 256 element for FileInputStream? It looks loke that: " int[] byteCountArray = new int[256]; " But you don´t know what is in the file so why you limit to number of ASCII control characters ? I probably didn´t understand something...

for months i postponed studying maps because looked to difficult to remember. 2 days ago after a long time i decide it to go back on chapter 8 and read about them. now when i saw this task i immediately said to myself "this is easy to do with a Map", and took me less than 10 minutes to solve this. i really liked this one.

Wow, got it in the first try with no test file. Did not expect that!

I was using ArrayList, SetList, HashMap to solve this task. It takes me 40 minutes. but I didn't understand what they excatly want from me at the begining.

task1803 () CLARIFICATION: the task description may seem a bit vague but I just got my code to pass by taking the text literally (i.e. reporting a space-separated string of numbers corresponding to the octet values that occur most often in the input). 'octet' stands for 'unsigned byte', i.e. values between 0 and 255.

Don't use static variables!!!

Don't use readAllBytes() method to solve this one. If you do so your program won't compile.

Yup. Hard. Took ages.

I had to use two nested for loops (total of four for loops) to get the most occurring bytes to display . Put everything in an arraylist first. Didn't think it'd be so difficult. Took hours.