Find a substring

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The getPartOfString method must return the substring that begins with the character after the first space and ends with the end of the word that follows the 4th space. Example: "CodeGym is the best place to learn Java." Result: "is the best place" Example: "Amigo and Diego are best friends!"

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matemate123

Level 32 , Kraków, Poland

8 March, 05:57

Hint: Most misleading in this task is "HARD" and "one star".

Jomar Tayactac

Level 2 , Winnipeg, Canada

Expert

26 May 2022, 16:17

"\\s\\S+"

Adrian

Level 27 , Spanish Town, Jamaica

2 March 2021, 18:40

This task does not want a "word" that follows the 4th whitespace, it wants the substring that follows it. or more generally, any character(s) that is not a whitespace. "hello my name is ^&*%#" returning "my name is ^&*%#" will pass. I wasted a lot of time on this because the two approaches I came up with (one using regex the other a for loop) would have thrown it an exception if the character after the 4th space was not a word character.

Justin Smith

Level 38 , Greenfield, USA, United States

12 December 2021, 14:07

This appears to be true and CodeGym should clarify what they mean by a word, especially since there is a task in another lesson earlier that uses the regex definition of a word character and CodeGym doesn't explain that either.

ugabuga

Level 31

2 January 2022, 07:59

I too wasted a lot of time thinking I have to discard any punctuation characters and other non alphanumericals after the last word. CodeGym should clarify!!

matemate123

Level 32 , Kraków, Poland

8 March, 05:49

When I start thinking second hours for what I forgot to prevent and go to discuss panel to find out that in this task logic is opposite :D

KIN SOCHEAT

Level 34 , Phnom Penh, Cambogia

18 April 2020, 03:52

don't use "\\W'' can pass only (" ").