Wait and see

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All exceptions that occur while the Solution thread is running must be handled by one of these options: 1. If it's an Error, then display "Can't keep running". 2. If it's an Exception, then display "Needs handling". 3. If it's a Throwable, then display "Wait and see". Implement this logic.

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Justin Smith

Level 38 , Greenfield, USA, United States

19 January 2022, 20:59

Hidden condition: The messages are meant to be exclusive of each other. In other words, only one message should ever be displayed. For example, e is always a Throwable (per method definition), which would imply based on the stated conditions that it should show the message for a Throwable regardless of whether or not e is also an Error or Exception. Only looking at the solution made this requirement clear.

Adrian

Level 27 , Spanish Town, Jamaica

20 January 2022, 00:51

so funny story, I just solved this task, read up on throwable and saw that Exception and Error are subclasses, realized I could use the isinstanceof operator, but my code wouldn't verify. turns out it's because I had an "if" instead of "else if" my issue is, while e is always a throwable, it is not an instance of either of its subclasses, so I can't see it being possible for more than one output to get printed

Baurzhan Konurbayev

Level 40

4 April 2021, 13:35

When I used currentThread() to set exception handler, it didn't work for me. So, I had to use this instead.