How to solve this thing ??

Question sur la mission

Mission n°3 sur les conversions des types d'entiers

Syntaxe Java, Niveau 10, Leçon 4

Résolues

Comment résoudre cela

Ajoute une conversion de type pour obtenir la réponse suivante : b = 0
float f = (float)128.50;
int i = (int)f;
int b = (int)(i + f);

Impératifs :

Le programme doit afficher du texte à l'écran.
Ne modifie pas la commande de sortie écran.
La méthode main() doit contenir une variable float appelée « f ».
La méthode main() doit contenir une variable int appelée « i ».
La méthode main() doit contenir une variable int appelée « b ».
Ne change pas la valeur initiale des variables lors de l'initialisation. Tu peux seulement ajouter des opérateurs de conversion.
Le programme doit afficher le nombre 0.

package fr.codegym.task.task10.task1003; /* Mission n°3 sur les conversions des types d'entiers */ public class Solution { public static void main(String[] args) { float f = (float) -128.50; int i = (int) f; int b = (int)(float) (i + f); System.out.println(b); } }

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Guadalupe Gagnon

niveau Tampa, Tampa, United States

9 novembre 2020, 15:04

solution

When converting a larger primitive down to a smaller primitive, if the larger data type is beyond the max/min values of the smaller data type, then the sign (negative or positive) gets flipped. If the larger number were exactly one past the max/min values of the smaller number, then the flip would take it to the bounds of the opposite sign. For each additional value beyond it will be adjusted accordingly For example, lets say you had a very large data type and then you wanted to convert it to a data type that can hold the 20 numbers (-10 to 9). If the larger data type was in that range then there would be no problem, so any numbers -10 to 9 would be a perfect conversion. Any numbers beyond that range would flip the sign and then adjust. So, briefly, this is how it would work: Larger # ---> Smaller # 9 to 9 10 to -10 // flips to opposite boundary of -10 11 to -9 12 to -8 ....... 19 to -1 20 to 0 21 to 1 22 to 2 This is how it would work for any conversion larger to smaller. I recommend first resetting the task. It looks like you may have made an illegal change. Once reset research the max/min values of the primitive types in Java while considering what I have said here. There is one primitive that matches the range of this task and would properly flip on line 10 to arrive at the correct answer.