import java.util.Objects;
public class Character {
private String Name;
public Character(String name) {
Name = name;
}
public String getName() {
return Name;
}
public void setName(String name) {
Name = name;
}
public static void main(String[] args) {
Character character1 = new Character("Arnold");
System.out.println(character1.getName());
System.out.println(character1.hashCode());
Character character2 = new Character("Arnold");
System.out.println(character2.getName());
System.out.println(character2.hashCode());
System.out.println(character2.equals(character1));
}
}
プログラムを実行した結果:
Arnold
1595428806
Arnold
1072408673
false
コンソール内の 2 つの 10 桁の数字はハッシュコードです。同じ名前を持つオブジェクトを同じものにしたい場合はどうすればよいでしょうか? 私たちは何をすべきか？答えは、CharacterクラスのObjectクラスのhashCode()メソッドとequals()メソッドをオーバーライドする必要があるということです。IDEA IDE ではこれを自動的に行うことができます。キーボードでalt + insertを押して、 Generate -> equals() and hashCode()を選択するだけです。 この例の場合、次のコードになります。
import java.util.Objects;
public class Character {
private String Name;
public Character(String name) {
Name = name;
}
public String getName() {
return Name;
}
public void setName(String name) {
Name = name;
}
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (!(o instanceof Character)) return false;
Character character = (Character) o;
return getName() != null ? getName().equals(character.getName()) : character.getName() == null;
}
@Override
public int hashCode() {
return getName() != null ? getName().hashCode() : 0;
}
public static void main(String[] args) {
Character character1 = new Character("Arnold");
System.out.println(character1.getName());
System.out.println(character1.hashCode());
Character character2 = new Character("Arnold");
System.out.println(character2.getName());
System.out.println(character2.hashCode());
System.out.println(character2.equals(character1));
}
}
import java.util.Date;
public class Student {
String surname;
String name;
String secondName;
Long birthday; // Long instead of long is used by Gson/Jackson json parsers and various orm databases
public Student(String surname, String name, String secondName, Date birthday ){
this.surname = surname;
this.name = name;
this.secondName = secondName;
this.birthday = birthday == null ? 0 : birthday.getTime();
}
//Java hashcode example
@Override
public int hashCode(){
//TODO: check for nulls
//return surname.hashCode() ^ name.hashCode() ^ secondName.hashCode() ^ (birthday.hashCode());
return (surname + name + secondName + birthday).hashCode();
}
@Override
public boolean equals(Object other_) {
Student other = (Student)other_;
return (surname == null || surname.equals(other.surname) )
&& (name == null || name.equals(other.name))
&& (secondName == null || secondName.equals(other.secondName))
&& (birthday == null || birthday.equals(other.birthday));
}
}
そして、Mainクラスがその作業をデモンストレーションします。
import java.util.Date;
import java.util.HashMap;
import java.util.Hashtable;
public class Main {
static HashMap<Student, Integer> cache = new HashMap<Student, Integer>(); // <person, targetPriority>
public static void main(String[] args) {
Student sarah1 = new Student("Sarah","Connor", "Jane", null);
Student sarah2 = new Student("Sarah","Connor", "Jane", new Date(1970, 01-1, 01));
Student sarah3 = new Student("Sarah","Connor", "Jane", new Date(1959, 02-1, 28)); // date not exists
Student john = new Student("John","Connor", "Kyle", new Date(1985, 02-1, 28)); // date not exists
Student johnny = new Student("John","Connor", "Kyle", new Date(1985, 02-1, 28)); // date not exists
System.out.println(john.hashCode());
System.out.println(johnny.hashCode());
System.out.println(sarah1.hashCode());
System.out.println();
cache.put(sarah1, 1);
cache.put(sarah2, 2);
cache.put(sarah3, 3);
System.out.println(new Date(sarah1.birthday));
System.out.println();
cache.put(john, 5);
System.out.println(cache.get(john));
System.out.println(cache.get(johnny));
cache.put(johnny, 7);
System.out.println(cache.get(john));
System.out.println(cache.get(johnny));
}
}
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