잡을 수 있으면 잡아 봐

Esteemed colleagues, things are getting serious. We're starting sting operation to catch exceptions. The secret CodeGym center has sent the following task, and I quote: "Catch (and display the type of) the exception that occurs when the following code is executed: int a = 42 / 0;". Note: Complete this task immediately.

In Java, an exception is an object. And it has a type, of course. This all seems vague until you start working with them. Practice will dispel the uncertainty. Be more confident in catching exceptions: catch and display the exception (indicating its type) that occurs when executing the following code: String s = null; String m = s.toLowerCase().

We're mastering the mechanism for handling errors in the program. By that I mean exceptions. This time, your task is to catch exceptions when working with arrays. An application has the following lines of code: int[] m = new int[2]; m[8] = 5; Catch the exception that occurs when this code is executed, and then display it on the screen and indicate its type.

By the ninth level, we've already got some idea of List collections, and exceptions. Let's bring this knowledge together: catch exceptions when executing the following code: ArrayList<String> list = new ArrayList<String>(); String s = list.get(18); Catch and display the exception on the screen, indicating its type.

We have some questionable code. It's time to deploy an agent to intercept (catch) exceptions. Here's the code: HashMap<String, String> map = new HashMap<String, String>(null); map.put(null, null); map.remove(null); Agent, your task, as usual, is to catch the exception and display it on the screen. Don't forget to only display the exception type.

Another task about catching exceptions arrived today at the secret CodeGym center. This time, we have to catch an exception and immediately display it on the screen. Don't forget to indicate its type. The exception in question will occur when the following code is executed: int num = Integer.parseInt("XYZ"); System.out.println(num).