Any better way?

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Hello i was wondering if there is shorter way to write this code something like this: if (a>b,c) or if (a>b&&c) to get one number and check if it's smaller or larger than rest of numbers. or there is only way by checking it one by one? thanks for answers

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Dawid

Poziom 8 , Poland

7 listopada 2023, 09:38

thank you <3 i've already finished task. was just wondering if there were any other shorter ways and sure there are. Glad to see something new i can learn

Thomas

Poziom 41 , Bayreuth, Germany

6 listopada 2023, 13:41

Without knowing what you currently have here are some ways to get the max out of 4 ints

import java.util.Arrays;
import java.util.Scanner;
import java.util.stream.IntStream;

public class FindMax {
    public static void main(String[] args) {
        Scanner console = new Scanner(System.in);
        int[] data = new int[4];
        for (int i = 0; i < data.length; i++) {
            data[i] = console.nextInt();
        }
        System.out.println(maxOf4CompareEach(data[0], data[1], data[2], data[3]));
        System.out.println(maxOf4Compare2(data[0], data[1], data[2], data[3]));
        System.out.println(maxOfNStream(data));
        System.out.println(maxOfNArraysSort(data));
    }


    private static int maxOf4CompareEach(int a, int b, int c, int d) {
        if (a > b && a > c && a > d)
            return a;
        else if (b > c && b > d)
            return b;
        else if (c > d)
            return c;
        else
            return d;
    }

    private static int maxOf4Compare2(int a, int b, int c, int d) {
        return Math.max(Math.max(Math.max(a, b), c), d);
    }

    private static int maxOfNStream(int... n) {
        return IntStream.of(n).max().getAsInt();
    }

    private static int maxOfNArraysSort(int... n) {
        Arrays.sort(n);
        return n[n.length - 1];
    }
}