can anyone help me

Question about the task

Under discussion

package com.codegym.task.task02.task0217; /* Minimum of four numbers */ public class Solution { public static int min(int a, int b, int c, int d) { //write your code here int e = min( a, b); if((a<=b) && (a<=c) && (a<=d)) { return a; } if((b<=a) && (b<=c) && (b<=d)) { return b; } if((c<=a) && (c<=b) && (c<=d)) { return c; } if((d<=a) && (d<=b) && (d<=c)) { return d; } return 0; } public static int min(int a, int b) { //write your code here if((a<=b)) { return a; } else { return b; } return e; } public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } }

Write a function that computes the minimum of four numbers.
The function min(a, b, c, d) should use (call) the function min(a, b)

Hint:
You need to write the body of the two existing min functions.

Requirements:

The program should display text on the screen.
The min methods should not display text on the screen.
The main method should call min(a, b) and min(a, b, c, d).
The main method should display the result of the min methods. Each time, on a new line.
The min(a, b) method must return the minimum of the numbers a and b.
The min(a, b, c, d) method must use the min(a, b) method.
The min(a, b, c, d) method must return the minimum of the numbers a, b, c, and d.

Comments (1)

Popular
New
Old

You must be signed in to leave a comment

Gellert Varga

Level 23 , Szekesfehervar, Hungary

13 September 2021, 19:58

Line 41: the variable 'e' is undefined. "Cannot find symbol". You didn't declare such a variable in this method. The variable 'int e' on line 11 is a so-called local variable. This means it only exists between lines 9 and 30, only in that method. You can't use it after that, because it doesn't exist afterwards. Line 41: 'unreachable statement' - JVM said this. This 'return' command can be never executed. So this is 'unreachable' for the JVM. This is because the if-else structure before line 41 covers all existing cases. The method already knows what to return in all possible case. There is no way for the program to ever reach this new return command in line 41, because it will surely exit the method before it does. (Execution of the return command causes an immediate exit from the method. If return is executed, no other commands can be added in the method.)