So i need help.

Frage zur Aufgabe

In der Diskussion

Well first of all this whole theme is kinda difficult for me. The Problem here is that the programm times out while verfication and i dont know why. Would be nice if you have any tipps here. If you have any good articel about streams please let me know or other ideas to understand the theme better.

Lies 3 Dateinamen von der Konsole ein: file1, file2, file3.
Teile file1 wie folgt auf:
Schreibe die erste Hälfte der Bytes in file2 und die zweite Hälfte der Bytes in file3.
Wenn die Anzahl der Bytes in file1 ungerade ist, dann muss file2 die größere Hälfte enthalten.
Schließe die Streams.

Anforderungen:

Das Programm muss dreimal einen Dateinamen von der Konsole lesen.
Verwende FileInputStream, um aus einer Datei zu lesen, und FileOutputStream, um in Dateien zu schreiben.
Die erste Hälfte der Bytes in der ersten Datei muss in die zweite Datei geschrieben werden.
Die zweite Hälfte der Bytes in der ersten Datei muss in die dritte Datei geschrieben werden.
FileInputStream und FileOutputStream müssen geschlossen werden.

package de.codegym.task.task18.task1808; /* Eine Datei teilen */ import java.io.*; public class Solution { public static void main(String[] args) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); File file1 = new File(reader.readLine()); File file2 = new File(reader.readLine()); File file3 = new File(reader.readLine()); FileInputStream inStream = new FileInputStream(file1); reader.close(); FileOutputStream outStream1 = new FileOutputStream(file2); FileOutputStream outStream2 = new FileOutputStream(file3); while (inStream.available() > 0){ if (file1.length() %2 == 0){ byte [] buffer1 = new byte [(int) file1.length()/2]; int count = inStream.read(buffer1); outStream1.write(buffer1,0 ,count); byte [] buffer2 = new byte [(int) file1.length()/2]; int count1= inStream.read(buffer2); outStream2.write(buffer2,0 ,count1); }else if (file1.length() %2 != 0 ){ byte [] buffer1 = new byte [(int) file1.length()/2+1]; int count = inStream.read(buffer1); outStream1.write(buffer1,0 ,count); byte [] buffer2 = new byte [(int) file1.length()/2]; int count1= inStream.read(buffer2); outStream2.write(buffer2,0 ,count1); } } inStream.close(); outStream1.close(); outStream2.close(); } }

Kommentare (3)

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Seb

Level 41 , Crefeld, Germany

27 April 2020, 22:23

nützlich

You can try to check whether the number of bytes in the file is odd or even before starting the loop on line 22. Then you can create two new byte arrays - one for the first half and one for the second half - also before the while loop. And now you can move into the while loop and write the first half of the bytes of file1 to the buffer for file2 and the second half of the bytes of file1 to the buffer for file3. Good luck. ;-)

Max

Level 26 , Nuremberg, Germany

28 April 2020, 10:24

Thank you for the tips. Do you have any idea why its timing out. I have this problem pretty often.

Seb

Level 41 , Crefeld, Germany

28 April 2020, 15:30

A timeout oftentimes has something to do with a loop or an open stream in the program. I do not see an obvious mistake in this regard in your program though. There's no infinite loop and you're closing the streams. :-) You could eventually try to use the try-with-resources construct, which takes care of closing the streams. Maybe that helps. Something like: try (FileInputStream inStream = new FileInputStream(file1); FileOutputStream outStream1 = new FileOutputStream(file2); FileOutputStream outStream2 = new FileOutputStream(file3)) { // your program's logic // including the while loop } catch (FileNotFoundException e) {} catch (IOException e) {}