error in variable declaration

Under discussion

Int result has been declared at line 14 error: cannot find symbol result; public class Codegym

public class Codegym
{
	public static int number = 25;

    public static void main(String[] args)
    {

    	Codegym cg = new Codegym();
    	cg.square();
    	System.out.println(result);

    }
    public int square(){
    	int result = number*number;

    }

}

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Nouser

Level 36 , Germany

2 January 2021, 12:53

useful

variables have a scope. While fields are visible in the entire class, local variables are just visible inside the block they are declared (and inner nested blocks)

{
    int var;
    //var is visible
    {
        //var is visible
    }
}
//var is not known here

So instead of

System.out.println(result);

write

System.out.println(cg.square());

This will call the method square, that one is doint its claculation and returning its result... think of the call of the method beeing replaced with the return value. For that to work you need to return the result in your square mthod. At its end write

return result;

Dinesh

Level 7 , Delhi, India

3 January 2021, 03:45

Thanks for explaining so good. It worked.😌

Dinesh

Level 7 , Delhi, India

3 January 2021, 12:14

Help me over this what i am doing wrong? public class Codegym{ double a =5; public static void main(String[]args){ System.out.println(sqr()); double sqr(double a) { return a*a; } } }

remote87

Level 18 , Sofia, Bulgaria

2 January 2021, 07:20

When you use a method which is not void you have to RETURN a value. Get it? public INT square() has to return something

Dinesh

Level 7 , Delhi, India

2 January 2021, 11:42

Ok But when I changed the method to void I didn`t see any change in the error. and when I keep the INT and return the result as return result; int the last line of the method square () i didn`t see any change in error