EveryThing is good , but in this task they say I am wrong

Question about the task

Finding data inside a file

Java Core, Level 8, Lesson 11

Resolved

Just copy this code and run you see that everything in this code is running , but third point say I am made a mistake.

Read a file name from the console.
Search the file for information related to the specified id. Display it in the format used in the file.
The program is started with one argument: id (an int).
Close the streams.

The file data is separated by spaces and stored in the following order:
id productName price quantity
where id is an int
productName is a String — it can contain spaces
price is a double
quantity is an int

The information for each product is stored on a separate line.

Requirements:

The program should read a file name from the console.
Create an input stream for the file.
The program should search the file and display information related to the specified id passed as the first argument.
The stream used to read the file must be closed.

package com.codegym.task.task18.task1822; /* Finding data inside a file */ import java.io.*; import java.util.*; public class Solution { public static void main(String[] args) throws IOException{ Scanner in = new Scanner(System.in); String fileName = in.nextLine(); BufferedReader reader = new BufferedReader(new FileReader(fileName)); String s ; while ((s = reader.readLine()) != null) { if (s.startsWith(args[0])) { System.out.println(s); } } reader.close(); } }

Comments (2)

Popular
New
Old

You must be signed in to leave a comment

Bill Nguyen

Level 22 , Ho Chi Minh, Vietnam

6 August 2019, 13:57

Thank you very much.

Nithin

Level 35 , Hyderabad, India

28 July 2019, 09:49

solution

Suppose if args[0] = 5 and the data in the file is 5 productName price quantity 55 productName price quantity then instead of printing only first one you are printing both. Even if you add break after line 20 we don't know whether the data in the file is sorted by id or not. So the best way is split the string and check whether first part is equal to given argument or not

while ((s = reader.readLine()) != null) {
            String[] arr = s.split(" ");
            if(arr[0].equals(args[0])) {
                System.out.println(s);
                break;
            }
        }