Time out but it's work!

Question about the task

Resolved

Hello! I have a problem. The code doesn't match the condition... I got " time out". But if I use this code it works. What's wrong then?

public class Solution {

        public static void main(String[] args) throws IOException {
            // write your code here
            BufferedReader BFileName = new BufferedReader(new InputStreamReader(System.in));
            String FileName = BFileName.readLine();

            BufferedReader linjka = new BufferedReader(new InputStreamReader(System.in));
            FileWriter wpis = new FileWriter(FileName);
            String napis = linjka.readLine();
            while(!napis.equals("exit")){
                wpis.write(napis + "\n");
                napis = linjka.readLine();
            }
            wpis.close(); // zamykamy wpisywanie do pliku !!
            BufferedReader buff = new BufferedReader(new FileReader(FileName));
            String tekst = buff.readLine();

            while(tekst != null){
                System.out.println(tekst);
                tekst = buff.readLine();
            }
            BFileName.close();
            buff.close();
        }
    }

1. Read a file name from the console.
2. Read lines from the console until the user enters the "exit".
3. Write all the entered lines to the file, each on a new line.

Requirements:

The program must read the file name from the console.
Create and use a BufferedWriter object.
The program should not read anything from the file system.
The program must read lines from the console until the user enters "exit".
The program must write absolutely all of the entered lines (including "exit") to the file, each on a new line.
The main method should close the BufferedWriter object after using it.

package com.codegym.task.task13.task1319; import java.io.*; /* Writing to a file from the console */ public class Solution { public static void main(String[] args) throws IOException { // write your code here BufferedReader BFileName = new BufferedReader(new InputStreamReader(System.in)); String FileName = BFileName.readLine(); BufferedReader linjka = new BufferedReader(new InputStreamReader(System.in)); FileWriter wpis = new FileWriter(FileName); String napis = linjka.readLine(); while(!napis.equals("exit")){ wpis.write(napis + "\n"); napis = linjka.readLine(); } wpis.close(); // zamykamy wpisywanie do pliku !! BufferedReader buff = new BufferedReader(new FileReader(FileName)); String tekst = buff.readLine(); while(tekst != null){ System.out.println(tekst); tekst = buff.readLine(); } BFileName.close(); buff.close(); } }

Comments (3)

Popular
New
Old

You must be signed in to leave a comment

Paweł

Level 15 , Gromnik, Poland

18 January 2020, 21:31

The key was that i needed to use BufferedWriter and write all including "exit". That's the correct answer.

package com.codegym.task.task13.task1319;

import java.io.*;

/*
Writing to a file from the console

*/

public class Solution {

    public static void main(String[] args) throws IOException {
        // write your code here
        BufferedReader BFileName = new BufferedReader(new InputStreamReader(System.in));
        String FileName = BFileName.readLine();

        BufferedReader linjka = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter wpis = new BufferedWriter(new FileWriter(FileName));
        String napis = "";
        while (!napis.equals("exit")) {
            napis = linjka.readLine();
            wpis.write(napis + "\n");

        }
        wpis.close();

    }
}

Anthony Chalk

Level 30 , London, United Kingdom

18 January 2020, 21:10

useful

You don't need to display the contents of the file, so you can remove lines 25-33. Often with these tasks, even a small digression from the conditions will mean it doesn't verify

Paweł

Level 15 , Gromnik, Poland

18 January 2020, 21:32

Thanks for tip!