CodeGym /Java Blog /Java Math /Math.sqrt Method - Square Root in Java
Author
Pavlo Plynko
Java Developer at CodeGym

Math.sqrt Method - Square Root in Java

Published in the Java Math group
Although calculating a square root in Java isn’t such a common question for software development interviews, sometimes, an interview might ask you something like: “You have an integer x. Create a Java program that would calculate its square root”. To make sure that such a basic question doesn’t catch you off guard, let’s take a look at how to do square root in Java.

Square and Square Root: Reviewing Math Concepts

To make sure you have no confusion when dealing with squares and roots, let’s review the theory of this concept. A square of a number is that number multiplied by itself. If n = 4, then n^2 = 4 4 = 16. The square root of a number is the number that, if multiplied by itself, gives a given value X. For example, you have to find the square root of n = 16, by finding a number that, if elevated to the power of two gives 16, you will solve the problem. In the case of n, the square root of the number 16 is 4 (since 4 * 4 = 16).

How to Do Square Root in Java Using java.lang.Math.sqrt()

The most common way to find a square root of a number in Java is by applying the java.lang.Math.sqrt() method. Here’s the general syntax of the java.lang.Math.sqrt() method:

public static double sqrt(double a)
In the method, a is a value elevated to the power of two you want to get square root for. Onc a developer applies java.lang.Math.sqrt(), the method will return the positive square root of a (if the a is greater than 0). For negative arguments, java.lang.Math.sqrt returns a NaN output.

Special cases of java.lang.Math.sqrt() returns

As mentioned above, in most cases, the method returns positive values. However, there are a few specific cases a developer should be aware of when creating a root-finding program.
  • For arguments that have NaN values or are negative, the method will return a NaN result.
  • For arguments that are positive infinitely, the method will return an infinitely positive result.
  • For arguments consisting of a positive or negative zero, the square root of a will equal a.

Example of using java.lang.Math.sqrt()


package MyPackage;
 
public class SquareRoot2 {
 
    public static void main(String args[])
    {
        double a = 100;
   
        System.out.println(Math.sqrt(a));
        // For positive values, the output is the square root of x 
   
        double b = -81.00;
   
        System.out.println(Math.sqrt(b));
        // For negative values as input, Output NaN 
   
        double c = 0.0/0;
        // Input NaN, Output NaN 
   
        System.out.println(Math.sqrt(c));
   
        double d = 1.0/0; 
        // For inputs containing  positive infinity, Output positive infinity  
   
        System.out.println(Math.sqrt(d));
         
        double e = 0.0;
        // Input positive Zero, Output positive zero 
         
        System.out.println(Math.sqrt(e));
    }
         
}

Finding Square Roots in Java Practice Problem

Now that you know how to create a program that calculates square roots in Java, let’s take a look at how the concept fits into more advanced practice problems. For example, an interviewer might ask you to solve a quadratic equation. Let’s take a look at how to handle such a problem. Problem: solve a quadratic equation where a = 1, b = 5, c = 2. Solution:

import java.util.Scanner;
public class Exercise2 {

    
  public static void main(String[] Strings) {

        Scanner input = new Scanner(System.in);

            System.out.print("Input a: ");
            double a = input.nextDouble();
            System.out.print("Input b: ");
            double b = input.nextDouble();
            System.out.print("Input c: ");
            double c = input.nextDouble();

            double result = b * b - 4.0 * a * c;

            if (result > 0.0) {
                double r1 = (-b + Math.pow(result, 0.5)) / (2.0 * a);
                double r2 = (-b - Math.pow(result, 0.5)) / (2.0 * a);
                System.out.println("The roots are " + r1 + " and " + r2);
            } else if (result == 0.0) {
                double r1 = -b / (2.0 * a);
                System.out.println("The square root is " + r1);
            } else {
                System.out.println("There are no real square roots in the equation.");
            }

    }
}

Conclusion

This was a brief rundown on finding a square root of a number in Java. For a software development beginner, it’s a good idea to practice different scenarios (a>0, a<0, a = 0) to get a solid grasp of the concept. Once you understand the ins and outs of the java.lang.Math.sqrt method, start applying the method in complex programs, handling tasks like solving quadratic equations.
Comments
TO VIEW ALL COMMENTS OR TO MAKE A COMMENT,
GO TO FULL VERSION