CodeGym/Help with Java Tasks/double value

Level 8

29.07.2018
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double value

Question about the task

Resolved

not showing double value why??

The convertCelsiusToFahrenheit(int celsius) method accepts a value in degrees Celsius. The method should convert the temperature and return the value in degrees Fahrenheit.
The Celsius temperature (TC) and the Fahrenheit temperature (TF) are related by the following relationship:
TF = (9 / 5) * TC + 32.

Consider this example:
A value of 41 is passed to the convertCelsiusToFahrenheit method.

Example output:
105.8

Requirements:

The convertCelsiusToFahrenheit(int) method must be public and static.
The convertCelsiusToFahrenheit method must return a double.
The convertCelsiusToFahrenheit method should not display anything.
The convertCelsiusToFahrenheit method must correctly convert degrees Celsius to degrees Fahrenheit and return the result.

package com.codegym.task.task01.task0130; /* Our first converter! */ public class Solution { public static void main(String[] args) { System.out.println(convertCelsiusToFahrenheit(41)); } public static double convertCelsiusToFahrenheit(int celsius) { double TF= (double)((celsius)*9/5) + 32; return TF; } }

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juan

Level 5 , Conroe, United States

23 May 2019, 12:37

package com.codegym.task.task01.task0130; /* Our first converter! */ public class Solution { public static void main(String[] args) { double TC = 41; System.out.println(convertCelsiusToFahrenheit(41)); } public static double convertCelsiusToFahrenheit(int TC) { double TF = 9 / 5.0 * TC + 32; return TF; } }

hidden #10448869

Level 2

19 May 2019, 11:40

double fahrenheit = 9 / 5.0 * (celsius + 32); return fahrenheit; Gives me 73.0. How to get the expected result?

shubham ojha

Level 3 , Delhi, India

23 August 2018, 15:00

double TF=(41.00*9/5) + 32; return TF;

-2

Deepak kumar

Level 2 , gurgaon, india

18 August 2018, 17:52

use below code as it is to solve this task

public class Solution {
    ...
}

Roman

Level 41

21 August 2018, 09:44

Posting the solution in the comments is prohibited.

Supriya Kesharwani

Level 3 , Indore, India

13 August 2018, 16:42

declare TF. as we have to calculate TF, not TC manipulate formula according to it. return TF instead of 0.

shubham ojha

Level 3 , Delhi, India

23 August 2018, 16:31

double fahrenheit = 9 / 5.0 * celsius + 32; return fahrenheit;

Anonymous #11341350

Level 6 , Spain

10 May 2023, 07:32

it works

Ankur Chauhan

Level 3

3 August 2018, 14:02

Finally after several attempts I have been able to pass this task with below code. ... just return the value of variable instead of "0" in convertCelsiusToFahrenheit(int celsius) function.

Sushant

Level 4 , goa, india

3 August 2018, 07:07

no one solved it correctly. can anyone have a different solution to it?

public class Solution {
    public static void main(String[] args) {
        System.out.println(convertCelsiusToFahrenheit(41));
    }

    public static double convertCelsiusToFahrenheit(int celsius) {
     double fahrenheit = ...;

        return 0;
    }

I m getting this answer correct as 105.8. bt output is not displaying. it always shows 0.0. anyone has a suggestion on this. u will get a correct answer in the calculator but not in this output

Pavlo Plynko Java Developer at CodeGym

8 August 2018, 07:48

Replace

return 0;

with

return fahrenheit;

Pavlo Plynko Java Developer at CodeGym

2 August 2018, 09:19

solution

Did you finish this task as a result?

Shivani

Level 3 , Rohtak, india

29 July 2018, 10:44

as the converter, method is declared as double so it will implicitly convert the integral value as double and return as double.... but here the issue is the exact value that is to be displayed should be 105.8 even though the correct answer is 105.0

Neptunian

Level 3 , Buenos Aires, Argentina

12 August 2018, 14:44

41 * (9/5) + 32 = 105.8 The correct anwser is indeed 105.8 but for some reason if you don't write any of the numbers involved in this division or multiplication as if it had a relevant value after the decimal point, the program rounds it up. For instance something like this would work for the program: 9.0 * celsius / 5 + 32 = fahrenheit or 9 * celsius / 5.0 + 32 = fahrenheit

Shivani

Level 3 , Rohtak, india

29 July 2018, 10:42

as per the real formula answer is 105.0 .... but here we need to display 105.8 for this use TF=celsius*9/5.0+32;