Method call problem

Question about the task

Under discussion

Done the task But can anyone explain how checkInterval(112) and checkInterval(10) is executed Flow of these two method i mean.

Write the checkInterval method. The method should check whether an integer is in the range from 50 to 100 and display the result on the screen as follows: "The number a is not in the interval." or "The number a is in the interval.", where a is the method argument.

Example for 112:
The number 112 is not in the interval.

Example for 60:
The number 60 is in the interval.

Requirements:

The program should display text on the screen.
The main method should not call System.out.println or System.out.print().
The main method must call the checkInterval method.
The checkInterval method must be static void.
The checkInterval method should display text on the screen in accordance with the task conditions.

package com.codegym.task.task04.task0410; /* Come on, lucky seven! */ public class Solution { public static void main(String[] args) { checkInterval(60); checkInterval(112); checkInterval(10); } public static void checkInterval(int a) { //write your code here if(a>50&&a<100) System.out.println("The number "+ a + " is in the interval" ); else System.out.println("The number "+ a + " is not in the interval"); } }

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Gellert Varga

Level 23 , Szekesfehervar, Hungary

27 May 2020, 19:13

Line 11: checkInterval(112); This code calls the line 15 checkInterval() method and sends the value '112' to the method to the line 15. Line 15: this metod receives this value. It will be named here as variable 'a'. So: int a = 112. Line 17 condition: (112>50 AND 112<100): 112>50: true! 112<100: false! true AND false = FALSE! (It would be true only if both of conditions are true.) The condition is false, so the program skips the execution of line 18, and goes to execute the 'else' thread: "The number is not in the interval" (Line 20)