Using the while loop, i don't understand what's wrong.

Question about the task

Task about algorithms

Java Syntax, Level 5, Lesson 12

Resolved

WHat could go wrong?

Write a program that:
1. reads a number N (must be greater than 0) from the console
2. reads N numbers from the console
3. Displays the maximum of the N entered numbers.

Requirements:

The program should read the numbers from the keyboard.
The program must display a number on the screen.
The class must have a public static void main method.
Don't add new methods to the Solution class.
The program should display the maximum of the N entered numbers.
The program should not display anything if N is less than or equal to 0.

package com.codegym.task.task05.task0532; import java.io.*; /* Task about algorithms */ public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int maximum = 0; //write your code here while(true){ int N=Integer.parseInt(reader.readLine()); if(N<=0) break; maximum=maximum>N?maximum:N; } System.out.println(maximum); } }

Comments (3)

Popular
New
Old

You must be signed in to leave a comment

Misiu

Level 41 , Gdansk, Poland

20 August 2020, 12:11

solution

1. Read N (count of numbers to compare) 2. If N <= 0 do nothing 3. Read N numbers and find a maximum among them (if N would be 3, then you have to read 3 numbers and find ...) (if N would be 17 then you have to read 17 numbers and find...)

atzur

Level 7 , Madrid, andorra

20 August 2020, 14:14

So you mean it is much better the for loop than the while, in this case.

Misiu

Level 41 , Gdansk, Poland

20 August 2020, 17:20

It doesn't matter. Use loop which you like. But read N numbers in that loop. for (i = 0, i < N, i++) (...) or while (N > 0) { .................. N-- }; But remember, first: if (N >0) { loop }