Can't make the 3rd and 4th requirements

Question about the task

Streets and houses

Java Syntax, Level 7, Lesson 4

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Not sure what do I do wrong. Thanks in advance!!

1. Create an array of 15 integers.
2. Populate it with values from the keyboard.
3. Let the array index represent the house number. The array value at a particular index represents the number of people living in the corresponding house.
Houses with odd numbers are located on one side of the street. Those with even numbers are on the other side. Find out which side of the street has more people living on it.
4. Display the following message: "Odd-numbered houses have more residents." or "Even-numbered houses have more residents."

Note:
The house at index 0 is considered even.

5. If the number of residents on each side of the street is the same, then output nothing.

Requirements:

The program must create an array of 15 integers.
The program should read numbers for the array from the keyboard.
The program should display "Odd-numbered houses have more residents." if the sum of odd array elements is greater than the sum of even ones.
The program should display "Even-numbered houses have more residents." if the sum of even array elements is greater than the sum of odd ones.
The program should not output text to the console if the number of residents on each side is the same.

package com.codegym.task.task07.task0706; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.*; /* Streets and houses */ public class Solution { public static void main(String[] args) throws Exception { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int oddsum = 0; int evensum = 0; int [] list = new int [15]; for (int i=0;i<15;i++) { String s = br.readLine(); list[i] = Integer.parseInt(s); } for (int i=0;i<15;i++) { if (list[i] % 2 !=0) oddsum += list[i]; } for (int i=0;i<15;i++) { if (list[i] % 2 ==0) evensum += list[i]; } if (oddsum > evensum) System.out.println("Odd-numbered houses have more residents."); else if (evensum > oddsum) System.out.println("Even-numbered houses have more residents."); } }

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Guadalupe Gagnon

Level 37 , Tampa, United States

19 October 2020, 17:09

solution

The task wants you to count the number of residents living on each side of the street and output which side has the most residents. Each index represents a house number and each value inside the index represents the number of residents. So if you had an array with these values: {3, 2, 5, 4, 3, 6} - even index residents would be 3, 5, 3 (at even indices 0, 2, 4) for a total of 11 - odd index residents would be 2, 4, 6 (at odd indices 1, 3, 5) for a total of 12 Visually, that would look like this: even street odd 3 | | 2 5 | | 4 3 | | 6 ---------------------------- 11 12 It should therefore output that the odd side has the greater residents.

Timothy Chan

Level 11 , Hong Kong, Hong Kong

19 October 2020, 18:03

for (int i=0;i<15;i++) {
    if (i==0 || i%2==0)
        evensum += list[i];
    else
        oddsum += list[i];
}

Timothy Chan

Level 11 , Hong Kong, Hong Kong

19 October 2020, 18:04

Thanks sir! Just realized I misunderstood the question and made the above change between line 25 and 33 and it is correct now!

Guadalupe Gagnon

Level 37 , Tampa, United States

19 October 2020, 18:21

Glad you got it! Just fyi on the code you shared:

for (int i=0;i<15;i++) {
    if (/*i==0 || */i%2==0) // 0 % 2 equals 0, you can just use the second equation for this
        evensum += list[i];
    else
        oddsum += list[i];
}