Outputs correct but doesnt pass 4th Check

Question about the task

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My code runs fine - gives the ordinal index of the unique number. If i input the same value 3 times, nothing prints - but yet the fourth check remains unpassed. Any ideas? Thanks in advance.

Use the keyboard to enter three integers. One of the numbers is unique. The other two are identical. Display the ordinal number of the number that is different from the others.

Example for 4 6 6:
1

Example for 6 6 3:
3

Requirements:

The program should read the numbers from the keyboard.
The program should use System.out.println() or System.out.print().
The program should display the ordinal number of the number that is different from the others.
If all the numbers are different, don't display anything.

package com.codegym.task.task04.task0424; /* Three numbers */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(reader.readLine()); int b = Integer.parseInt(reader.readLine()); int c = Integer.parseInt(reader.readLine()); if (a != b && a != c) { System.out.println(1); } if (b != a && b != c) { System.out.println(2); } if (c != a && c != b) { System.out.println(3); } // // if (a == b && a == c) { // System.out.println(""); // } } }

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Guadalupe Gagnon

Level 37 , Tampa, United States

28 June 2021, 13:13

useful

The condition that is failing says: "If all the numbers are different, don't display anything." I duplicated this by entered 1, 2, 3 and it output: 1 2 3 This is a bug that needs to be fixed

Usman Full Stack Developer at QA

28 June 2021, 14:25

okay i see. i changed my code with an if statement at tthe start now that checks a, b and c are not same at the very top first. i just didntt read it properly i guess lol

public class Solution {
    public static void main(String[] args) throws Exception {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));

        int a = Integer.parseInt(reader.readLine());
        int b = Integer.parseInt(reader.readLine());
        int c = Integer.parseInt(reader.readLine());

        if (a != b && a != c && b != c) {

        } else if (a != b && a != c) {
            System.out.println(1);
        } else if (b != a && b != c) {
            System.out.println(2);
        } else if (c != a && c != b) {
            System.out.println(3);
        }

    }
}

thank you buddy

Guadalupe Gagnon

Level 37 , Tampa, United States

28 June 2021, 14:58

Mis-reading the conditions is a common mistake that is very easy to make, I'd be lying if i said I have never done it myself. That is actually the first thing I check when I click submit and it fails: I go back and re-read the directions to make sure I didn't miss or mistake anything.