What is wrong?

Question about the task

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Can somebody tell me what is wrong with my code? It seems like the second while is only used once. So if I add a "1" instead of the free space with my System.out.println("1"); it displays : $$$$$$$$$$1 1 1 1 1 1 1 1 1 1 I don't really understand why the second while loop is used only once. Arent't they nested properly?

package com.codegym.task.task04.task0433; /* Seeing dollars in your future */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here int a = 10; int b = 10; while (a > 0){ while (b > 0){ System.out.print("$"); b--; } System.out.println(""); a--; } } }

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nikk_shukla

Level 10 , Mumbai, India

15 May 2019, 08:14

public class Solution { public static void main(String[] args) throws Exception { int i=1; int j=1; while(i<=10){ while(j<=10) { System.out.print("$"); j++; } System.out.println(" "); j=1; i++; } } }

-1

Mahesh Hirpara

Level 7 , Ahmedabad, India

21 February 2019, 04:39

Dear MP Apply this Code : public class Solution { public static void main(String[] args) throws Exception { //write your code here int a = 10; int b = 10; while (a > 0) { while (b > 0) { System.out.print("$"); b--; } b=10; System.out.println(""); a--; } } }

Vadim

Level 8 , Hounslow, United Kingdom

6 April 2020, 10:33

can you explain to me why need to write after the first print.out, b=10;? i'am a little confused Thank you!

Adrian

Level 27 , Spanish Town, Jamaica

8 April 2020, 02:47

essentially, the code he uses means: keep checking if b is greater than zero (b>), if it is, count down. since the int variable "b" was initialized to 10. it will print the dollar sign 10 times. Because he uses (.print) the dollar sign stays in the same line. An interesting way of doing it, not the way i chose.

Guadalupe Gagnon

Level 37 , Tampa, United States

21 January 2019, 16:24

solution

Have you learned about for loops yet? Whenever a counter is needed a for loop is preferable to a while loop: This is the blueprint for a 'for' loop. for( <initializer> ; <condition> ; <change to counter> ) { // code } The big problem that i see is that once b = 0 ( after the first loop cycle ) it never is reset to 10 in the following cycles. This is why you have one full line and then blank lines thereafter. A for loop will change that as the inner loop is re-initialized with each iteration of the outer loop. Here is your same exact code using for loops instead:

for (int a = 10; a > 0; a--){
   for (int b = 10; b > 0; b--){
      System.out.print("$");
   }
   System.out.println(); // don't need to include anything if all you want is a new line
}

Level 8 , Wietzendorf, Germany

21 January 2019, 16:35

Yeah I'm familiar with for loops but this time I read the task and the while loop is necessary. Okay, so the while loop wont reset my b so I have to reset it .. I guess outside the second while loop.

Level 8 , Wietzendorf, Germany

21 January 2019, 16:37

I did not now about that missing reset, thank you as always !

while (a > 0){
            while (b > 0){
                System.out.print("$");
                b--;
            }
            System.out.println("");
            a--;
            if (b == 1);
            b = 10;
            }

This way it works as intended :)

Guadalupe Gagnon

Level 37 , Tampa, United States

21 January 2019, 16:50

LOL... you caught me not reading the task conditions ( we all do it ). I just read your question and code and went from there.. Glad you were able to make the proper correction from the examples i gave.

Level 8 , Wietzendorf, Germany

21 January 2019, 16:55

Now I got you :D But thanks anyways, at least my code works now :)