Can anyone explain me please the solution of the reverseArray() method?

Sorry, that was my first question :) The solution given by Codegym: public class Solution { public static void main(String[] args) { int[] array = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0}; printArray(array); reverseArray(array); printArray(array); } public static void reverseArray(int[] array) { for (int i = 0; i < array.length / 2; i++) { int temp = array[i]; array[i] = array[array.length - i - 1]; array[array.length - i - 1] = temp; } } public static void printArray(int[] array) { for (int i : array) { System.out.print(i + ", "); } System.out.println(); } } I don't understand the line: for (int i = 0; i < array.length / 2; i++). Why array.length is divided?

That's pretty much the usual approach for the desired result. You take the first element of the array and swap it with the last element, then you take the second element and swap it with the second last and so on. That's why you just need to iterate to array.length / 2. If the array is not even then there's no need anymore to swap the middle element and so the int division is OK (that for the loop definition).

int temp = array[i]; // saving in a temp variable, so the value still exists when overwriting that element in the next line
array[i] = array[array.length - i - 1]; // here you'd count backwards, last element then second last etc.

Thank you Thomas! I have not been here for a few days.

:) I'm not around that much either and the topic starter seems not to mind either. Hope all is well on your end?

Thanks, pretty much everything OK:)

Appreciate the code comments to figure this out !