Why i < args.lenght; and not args.lenght-1; ???

Question about the task

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For the conditions -d and -i i use a for(int i = 1; i < args.lenght-1; i++) and the task didn't pass. I changed in i < args.lenght; just like that... and pass, but i don't understand why? If args.lenght = 10 and args[0] = "-d", from 1 to 9 I have the rest of args array. If i loop until i = 10 I am not out of array!?

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Guadalupe Gagnon

Level 37 , Tampa, United States

9 February 2022, 22:11

The second condition of a for loop, the boolean, is checked prior to the loop and will break the loop before it starts a new cycle when the expression is false. As an example:

public static void main(String[] args) {
   for(int i = 0; i < 10; i++)
      System.out.println(i);
}

This code prints the numbers 0 through 9, but not 10. This is because when i equals 10 the boolean expression 10 < 10 will be false (10 is not less than 10) and the loop concludes.

Angel Stefan

Level 23 , Sibiu, Romania

9 February 2022, 22:50

What a silly question to ask, is crystal clear(now!) I am used to use i <= array.lenght-1; but now because i use only < is obvious that i must use array.lenght. Tk you! Ps: i think i need a good sleep! :)