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Question about the task

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public class Solution {
    private static List<String> strings;

    public static void main(String[] args) throws Exception {
        //write your code here
        strings = new ArrayList<String>();
        int max = 0;
        Scanner sc = new Scanner(System.in);
        for (int y = 0; y < 5; y++){
            String a = sc.next();
            strings.add(a);
        }
        max = strings.get(0).length();

        for (int x = 0; x < strings.size(); x++){
            if (strings.get(x).length() > max)
                max = strings.get(x).length();

        }
        for (int i = 0; i < 5; i++){
            if (max == strings.get(i).length())
                System.out.println(strings.get(i));

        }

    }

1. Initialize the list of strings.
2. Read 5 strings from the keyboard and add them to this list.
3. Using a loop, find the longest string in the list.
4. Display the string. If there is more than one, display each on a new line.

Requirements:

In the main method, initialize the Solution class's existing strings field to a new ArrayList<>.
The program should read 5 strings from the keyboard and write them to the list of strings.
The program should display the longest string.
If several strings qualify as the longest, then you need to display each of them on a new line.

package com.codegym.task.task07.task0708; import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.List; import java.util.Scanner; /* Longest string */ public class Solution { private static List<String> strings; public static void main(String[] args) throws Exception { //write your code here strings = new ArrayList<String>(); int max = 0; Scanner sc = new Scanner(System.in); for (int y = 0; y < 5; y++){ String a = sc.next(); strings.add(a); } max = strings.get(0).length(); for (int x = 0; x < strings.size(); x++){ if (strings.get(x).length() >= max) max = strings.get(x).length(); } for (int i = 0; i < 5; i++){ if (max == strings.get(i).length()) System.out.println(strings.get(i)); } } }

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hacks patel

Level 20 , Ahmedabad, India

1 March 2019, 13:23

//try this code import java.io.BufferedReader; import java.io.InputStreamReader; import java.util.Arrays; import java.util.Collections; public class ARR { public static void main(String [] args ) throws Exception { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String [] arr = new String[5]; for (int i = 0 ; i < 5 ; i++) { arr[i] = br.readLine(); } Arrays.sort(arr , Collections.reverseOrder()); System.out.println(arr[0]); int p = arr[0].length(); for(int i = 1 ; i < 5 ; i++) { if(p == arr[i].length()) { System.out.println(arr[i]); } } } }

-2

hacks patel

Level 20 , Ahmedabad, India

1 March 2019, 12:35

take all Strings in array then sort them by length display last string and then check condition if other String has same length if another string is available then display it also..

Roman

Level 41

13 February 2019, 13:46

Try to test your code with the strings:

qwe qwe
test1
test2
test3
test4