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Question about the task

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Java Syntax, Level 6, Lesson 8

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Where am I doing wrong?

Implement the main(String[]) method, which displays true if the element is contained in the passed array, otherwise false.
The array variable should not change the position of its elements.

To search for an element in an array, you need a binary search. To do this, use the static Arrays.binarySearch(int[], int) method of the Arrays class.
In the first argument, pass a sorted array to be searched. The second parameter is the element to be searched for.
The Arrays.binarySearch(int[], int) method returns the index of the query element, if such an element exists in the array.

You can use the Arrays.sort(int[]) method to sort the array.
During testing, the values of the variables in the Solution class will be different.

Requirements:

In the main(String[]) method, do not change the position of the elements in the array.
When the main(String[]) method is called, display true if the value of the element variable is contained in the array.
When the main(String[]) method is called, display false if the passed element is not contained in the array.
In the main(String[]) method, use a call to the Arrays.binarySearch(int[], int) method.

package en.codegym.task.pro.task05.task0519; import java.util.Arrays; /* Is anyone there? */ public class Solution { public static int[] array = {9, 8, 7, 6, 5, 4, 3, 2, 1}; public static int element = 5; public static void main(String[] args) { //write your code here int array2 []=Arrays.copyOf(array, array.length); Arrays.sort(array2); System.out.println(Arrays.binarySearch(array2,element)>0); } }

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Sumon

Level 9 , Karlsruhe, Germany

2 December 2023, 22:16

Problem solved. I had to consider if the value of element is 0, then the output should also be true.