Hey - check number 2 is not solved, can someone help me understand why?

Question about the task

Under discussion

package en.codegym.task.pro.task04.task0414;

import java.util.Scanner;

/*
There's never too much of a good thing
*/

public class Solution {
    public static void main(String[] args) {
        //write your code here
        Scanner scanner = new Scanner(System.in);
        String s;
        int number;
        do {
            s = scanner.next();
            number = scanner.nextInt();

            if(number <= 0 || number >= 5) {
                System.out.println(s);
            }
            else {
                for(int i = 0; i < number; i++) {
                    System.out.println(s);
                }
            }
        }
        while(scanner.hasNext());
    }
}

In this task, you need to:

Use the keyboard to read a string and a number (number variable) that is greater than 0 and less than 5.
Display the string number times using a do-while loop. Display each value on a new line.

If the value read in for the number variable is less than or equal to 0 or greater than or equal to 5, then the entered string must be displayed once.

Example input:
abc 2

Example output:
abc abc

Requirements:

The program should read data from the keyboard.
The program should display data on the screen.
The program should display the string number times.
The program should display the string once if number is less than or equal to 0 or greater than or equal to 5.
The program must use a do-while loop.

package en.codegym.task.pro.task04.task0414; import java.util.Scanner; /* There's never too much of a good thing */ public class Solution { public static void main(String[] args) { //write your code here Scanner scanner = new Scanner(System.in); String s; int number; do { s = scanner.next(); number = scanner.nextInt(); if(number <= 0 || number >= 5) { System.out.println(s); } else { for(int i = 0; i < number; i++) { System.out.println(s); } } } while(scanner.hasNext()); } }

Comments (2)

Popular
New
Old

You must be signed in to leave a comment

Thomas

Level 41 , Bayreuth, Germany

31 May, 21:31

You are asking for input in a loop and the abort condition is Scanner:hasNext() However hasNext() just blocks when there is no input anymore but it does not leave the loop. Means after your two inputs scanner still waits for the next input and that's also the problem for validation. It can not validate as it still hangs inside the loop (at least that's my guess).

Mattt321 Java Developer

1 June, 08:02

maybe - i gotta think about it more