program runs fine but wont verify

Question about the task

Streets and houses

Java Syntax, Level 7, Lesson 4

Archived

i cant see where is the problem

1. Create an array of 15 integers.
2. Populate it with values from the keyboard.
3. Let the array index represent the house number. The array value at a particular index represents the number of people living in the corresponding house.
Houses with odd numbers are located on one side of the street. Those with even numbers are on the other side. Find out which side of the street has more people living on it.
4. Display the following message: "Odd-numbered houses have more residents." or "Even-numbered houses have more residents."

Note:
The house at index 0 is considered even.

5. If the number of residents on each side of the street is the same, then output nothing.

Requirements:

The program must create an array of 15 integers.
The program should read numbers for the array from the keyboard.
The program should display "Odd-numbered houses have more residents." if the sum of odd array elements is greater than the sum of even ones.
The program should display "Even-numbered houses have more residents." if the sum of even array elements is greater than the sum of odd ones.
The program should not output text to the console if the number of residents on each side is the same.

package com.codegym.task.task07.task0706; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; /* Streets and houses */ public class Solution { public static void main(String[] args) throws Exception { BufferedReader rd = new BufferedReader(new InputStreamReader(System.in)); int[] house = new int[15]; int evenHouse = 0; int oddHouse = 0; for (int i =0; i<15; i++){ house[i] = Integer.parseInt(rd.readLine()); if (house[i]%2 == 0) evenHouse++; else oddHouse++;///write your code here } System.out.println(evenHouse>oddHouse ? "Even-numbered houses have more residents." : "Odd-numbered houses have more residents."); } }

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Khurram

Level 16 , Lahore, Pakistan

24 March 2019, 18:14

solution

the index represents the house number and the element at that index represents the number of the people in the house, you need to check the condition %2 == 0 with the index not with the element, because odd/even needs to be checked for the house numbers. also you need to add all the residents in the variables evenHouse or oddHouse. right now you are just adding 1 to them in every loop

Bazsó Benjámin

Level 20 , Szombathely, Hungary

24 March 2019, 22:50

if (i%2 == 0)
            evenHouse+=house[i];
            else
                oddHouse+=house[i];

thank you again :)