I dont understand what wrong?

Question about the task

18+

Java Syntax, Level 4, Lesson 6

Resolved

How can help me. In program everything work. But in CodyGym no. Where is my mistake ?

package com.codegym.task.task04.task0422; /* 18+ */ import java.io.*; import java.util.Scanner; public class Solution { public static void main(String[] args) throws Exception { Scanner sc=new Scanner(System.in); int a=sc.nextInt(); int b=sc.nextInt(); // int age=18; if(a>=18 | b>=18){ }else{ System.out.println("Grow up a little more"); } // if(a<18){ // System.out.println("Grow up a little more"); // }else if( b<18){ // System.out.println("Grow up a little more"); // }else{ // // System.out.println(); // } } }

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Evghenii

Level 13 , Chisinau, Moldova, Republic of

27 April 2019, 12:51

Thanks every body.I make it. The solution was in this public class Age18 { public static void main(String[] args) throws Exception { Scanner sc= new Scanner(System.in); String name=sc.nextLine(); int age=sc.nextInt(); if(age<=18 ){ System.out.println("Grow up a little more"); }else{ } } }

Serg

Level 17 , Minsk, Belarus

25 April 2019, 18:54

you need "age" as int and "name" as String with the Scanner you can use: Scanner scan = new Scanner(System.in); String name = scan.nextLine(); and if(age<18) { //If the age is less than 18, display "Grow up a little more" and nothing else. System.out.println("text from the task") } this is the end of the cycle /* If the age is greater than or equal to 18, don't display anything.*/ all other variants like "age>=18" shouldn't be printed

Brice Silidje

Level 9 , Douala, Cameroon

25 April 2019, 04:08

hope this will help: BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); //read name and age String name = reader.readLine(); int age = Integer.parseInt(reader.readLine()); //convert string to integer //Just need to check this. if(age < 18) System.out.println( "Grow up a little more");