Ideas ?? Lucky 7 7 7 output is quirky between 50 && 100 --- I am Stuck !

Question about the task

Under discussion

if(a > 50 && a < 100){
System.out.println("The number "+ a +" is not in the interval.");
}
else

System.out.println("The number "+ a +" is in the interval.");

Write the checkInterval method. The method should check whether an integer is in the range from 50 to 100 and display the result on the screen as follows: "The number a is not in the interval." or "The number a is in the interval.", where a is the method argument.

Example for 112:
The number 112 is not in the interval.

Example for 60:
The number 60 is in the interval.

Requirements:

The program should display text on the screen.
The main method should not call System.out.println or System.out.print().
The main method must call the checkInterval method.
The checkInterval method must be static void.
The checkInterval method should display text on the screen in accordance with the task conditions.

package com.codegym.task.task04.task0410; /* Come on, lucky seven! */ public class Solution { public static void main(String[] args) { checkInterval(60); checkInterval(112); checkInterval(10); } public static void checkInterval(int a) { // inRange = a >= 50 && a <= 100; // not with = ... that's not between // if a = inRange { if(a > 50 && a < 100){ System.out.println("The number "+ a +" is not in the interval."); } else System.out.println("The number "+ a +" is in the interval."); } }

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Дмитрий Даниленко

Level 6 , Kiev, Ukraine

24 May 2019, 12:37

you need to use "or" (||) instead of "and" (&&)

Thomas

Level 12 , Scottsdale, United States

24 May 2019, 06:11

Thank you kindly Mr. Potts )

a) why <= ? && >= ? doesn't seem like the spirit of between ? lol b) see attached --- I wasn't joking how many times I tweaked this code !

Howard Potts

Level 7 , Bangalore, India

24 May 2019, 05:03

useful

package com.codegym.task.task04.task0410; /* Come on, lucky seven! */ public class Solution { public static void main(String[] args) { checkInterval(60); checkInterval(112); checkInterval(10); } public static void checkInterval(int a) { //write your code here if(50<=a &&a<=100) System.out.println("The number " + a + " is in the interval."); else System.out.println("The number " + a + " is not in the interval."); } }