Works in the console but verification returns compile error

Question about the task

Under discussion

public class Solution {
    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));

        ArrayList<String> list = new ArrayList<>();
        while (true) {
            String s = reader.readLine();
            if (s.isEmpty()) break;
            list.add(s);
        }

        /*ArrayList<String> listUpperCase = new ArrayList<String>();
        for (int i = 0; i < list.size(); i++) {
            String s = list.get(i);
            listUpperCase.add(s.toUpperCase());
        }*/
        /*for (int i = 0; i < listUpperCase.size(); i++) {
            System.out.println(listUpperCase.get(i));
        }*/

        ArrayList<String> listEvenDuplicate = new ArrayList<>();
        for (int i = 0; i < list.size() ; i++) {
            int s = list.get(i).length();
            if (s % 2 == 0) {
                listEvenDuplicate.add(String.valueOf(list));
                System.out.print(listEvenDuplicate.get(i).repeat(2));
            }else if (s % 2 !=0) {
                listEvenDuplicate.add(list.toString());
                System.out.print(listEvenDuplicate.get(i).repeat(3));
            }

        }

    }
}

Task: The program takes in strings until the user enters an empty string (by pressing Enter). Then it converts the strings to uppercase ("mother" becomes "MOTHER") and displays them.

New task: The program takes in strings until the user enters an empty string (by pressing Enter).
Then the program builds a new list. If a string has an even number of letters, then the string is duplicated. If the number of letters is odd, then the string is repeated three times.
The program displays the contents of the new list.

Example input:
Cat Cats I

Example output:
Cat Cat Cat Cats Cats I I I

Requirements:

The program must read data from the keyboard.
The program should display as many strings as are entered.
If a string has an even number of letters, then you need to duplicate the string (as in the example).
If a string has an odd number of letters, then you need to repeat the string three times (as in the example).
The program should stop reading data from the keyboard as soon as the user enters an empty string (by pressing Enter).

package com.codegym.task.task07.task0727; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.ArrayList; /* Changing functionality */ public class Solution { public static void main(String[] args) throws IOException { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); ArrayList<String> list = new ArrayList<>(); while (true) { String s = reader.readLine(); if (s.isEmpty()) break; list.add(s); } /*ArrayList<String> listUpperCase = new ArrayList<String>(); for (int i = 0; i < list.size(); i++) { String s = list.get(i); listUpperCase.add(s.toUpperCase()); }*/ /*for (int i = 0; i < listUpperCase.size(); i++) { System.out.println(listUpperCase.get(i)); }*/ ArrayList<String> listEvenDuplicate = new ArrayList<>(); for (int i = 0; i < list.size() ; i++) { int s = list.get(i).length(); if (s % 2 == 0) { listEvenDuplicate.add(String.valueOf(list)); System.out.print(listEvenDuplicate.get(i).repeat(2)); }else if (s % 2 !=0) { listEvenDuplicate.add(list.toString()); System.out.print(listEvenDuplicate.get(i).repeat(3)); } } } }

Comments (3)

Popular
New
Old

You must be signed in to leave a comment

thinhnguyen

Level 24 , Danang, Viet Nam

18 June 2019, 16:09

You must add a space between two items. if (s % 2 == 0) { String duplicateValue = s + " " + s; } else if ...

hidden #10441159

Level 16

19 June 2019, 08:06

Is this causing the Compile error on line 38 ? i`ll try but seems a bit unlikely.

thinhnguyen

Level 24 , Danang, Viet Nam

20 June 2019, 14:01

I wrong in the previous answer. You don't need the function repeat(). Just need to check: int s = list.get(i).length(); if (s % 2 == 0) { String duplicateValue = list.get(i) + " " + list.get(i); listEvenDuplicate.add(duplicateValue ); } ... And then display a new list on the screen