"The server is unable to properly test your solution. Be sure you have all the classes you need. Be sure that your solution doesn't have any infinite loops."

Let's write an archiver. At a minimum, an archiver should be able to zip and unzip files.

Let's start with the first one.
We need an archive manager. It will perform operations on the archive file (a file that will be stored on disk and have the zip extension). The class that will handle this will be called ZipFileManager. But the most important class will be called Archiver.
Programming and other fields have a concept called full (absolute) and relative paths. First off, let's wrap our heads around what a path is, in general. A path is a set of symbols that indicates where in the operating system a file or folder is located.
A full or absolute path is a path that starts with the root directory. In Windows, a disk is generally considered the root directory.
An example of a full path in Windows is: C:\user\zips\Test1.zip.
A relative path is a path relative to a directory. For example, zips\Test1.zip is the relative path of the file Test1.zip in relation to the C:\user directory (folder). The path relative to the C:\user\zips directory would just be Test1.zip, and would match the file name.
Note that, by default, both the full and relative path to a file include the name of the file.
1. Create a ZipFileManager class
2. Add a private Path zipFile variable to the class. We will use it to store the full path to the archive that we will be working with.
3. Add a ZipFileManager(Path zipFile) constructor. Initialize the class's zipFile field.
4. Declare a public createZip(Path source) throws Exception method with, for now, an empty implementation.
The Path source parameter is a path to something that we will zip.
5. Create an Archiver class and add a main method to it.
6. In the main method:
6.1 Ask the user to enter the full path to the archive from the keyboard. Don't forget that the file name is also part of the full path.
6.2 Create a ZipFileManager object, passing in the archive's file name. Figure out how to get a Path from a String.

Hint: look into the Paths class's get() method.

6.3 Ask the user to enter the path to the file to be zipped. Don't confuse this with the archive file, which we already entered. This time, we need the file that we'll compress, not the one we're going to store the compressed data in.
6.4 Call the ZipFileManager object's createZip method, passing the path to be zipped.