I am getting correct output but yet error message is being shown. Please Help!

Question about the task

Under discussion

The Error Message : Be sure that the length of the longest sequence is calculated correctly when it is located at the end of the list of entered numbers. My Code:

public static void main(String[] args) throws IOException {
        //write your code here
        BufferedReader r = new BufferedReader(new InputStreamReader(System.in));
        int maxCount = 1;
        int count = 1;
        ArrayList<Integer> numList = new ArrayList<Integer>();

        for(int i = 0; i<10;i++){
            numList.add(Integer.parseInt(r.readLine()));

        }
        for(int i = 0;i<9;i++){
            loop2:
            for(int j = i+1;j<10;j++){
                if(numList.get(i) == numList.get(j)){
                    count++;
                    if(count>maxCount){
                        maxCount=count;
                    }
                }
                else{

                    count = 1;
                    break loop2;
                }
            }
        }

        System.out.println(maxCount);

    }

Please Help!

1. Create a list of numbers.
2. Use the keyboard to add 10 numbers to the list.
3. Display the length of the longest sequence of repeating numbers in the list.

Example for the list 2, 4, 4, 4, 8, 8, 4, 12, 12, 14:
3

The value is 3, because the longest sequence of repeating numbers is three fours.

Requirements:

The program must display a number on the screen.
The program should read values from the keyboard.
In the main method, declare an ArrayList variable with Integer elements and immediately initialize it.
The program should add 10 numbers to the collection in accordance with the conditions.
The program should display the length of the longest sequence of repeating numbers in the list.

package com.codegym.task.task08.task0812; import java.io.*; import java.util.ArrayList; import java.util.*; /* Longest sequence */ public class Solution { public static void main(String[] args) throws IOException { //write your code here BufferedReader r = new BufferedReader(new InputStreamReader(System.in)); int maxCount = 1; int count = 1; ArrayList<Integer> numList = new ArrayList<Integer>(); for(int i = 0; i<10;i++){ numList.add(Integer.parseInt(r.readLine())); } for(int i = 0;i<9;i++){ loop2: for(int j = i+1;j<10;j++){ if(numList.get(i) == numList.get(j)){ count++; if(count>maxCount){ maxCount=count; } } else{ count = 1; break loop2; } } } System.out.println(maxCount); } }

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Evghenii

Level 13 , Chisinau, Moldova, Republic of

1 September 2019, 14:49

Hello. I did it like this. public class Solution { public static void main(String[] args) throws IOException { ArrayList<Integer> li= new ArrayList<>(); int a=1; int b=1; Scanner sc= new Scanner(System.in); for (int i = 0; i <10 ; i++) { int bb=sc.nextInt(); li.add(bb); } for (int i = 0; i <li.size()-1 ; i++) { if (li.get(i).equals(li.get(i+1))){ a++; }else{ a=1; } if(a>b){ b=a; } } System.out.println(b); } } I Will be happy if it will help you.

Joseph

Level 22 , United States

1 September 2019, 00:38

I looked at your code and restructured it a little differently and did some testing. I took out the bit about the loop2: and the break statement in lines 24 and 35. I also took out the else statement. I moved the count = 1; to the nested if after maxCount=count; Then after that I put i++; right after the count = 1; I did testing with this and it seems to check out every time.

Joseph

Level 22 , United States

1 September 2019, 01:14

Actually it doesn't work entirely. So I changed it by removing the i++ and just adding a break statement after the if and nested if in line 32. So basically just remove else, add break and move count = 1; to nested if after maxCount = count;