Hashset correction for, cannot convert boolean to string line#28

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i read this article, but its not much help https://stackoverflow.com/questions/12014641/java-retrieving-an-element-from-a-hashset

public static Set<String> createSet() {
        //write your code here
        Set<String> s = new HashSet<String>();
        //s.add
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");
        s.add("Lsss");/*,"Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss"
                  ,"Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss"
                  ,"Lsss","Lsss");*/

              Set<String> ss = s.contains("L");
        return ss;

package com.codegym.task.task08.task0813; import java.util.Set; import java.util.HashSet; /* 20 words that start with the letter "L" */ public class Solution { public static Set<String> createSet() { //write your code here HashSet<String> s = new HashSet<String>(); //s.add s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss"); s.add("Lsss");/*,"Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss" ,"Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss","Lsss" ,"Lsss","Lsss");*/ return s; } public static void main(String[] args) { createSet(); } }

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Daniel Knox

Level 9 , Annfield Plain, United Kingdom

17 December 2018, 09:23

Each word has to be different. What are you doing when you have to make 50000 words?

gery

Level 9 , Islamabad, Pakistan

30 September 2018, 08:06

error is on line#28

Ankush Rajput

Level 25 , Bhopal, India

30 September 2018, 12:15

solution

Set<String> ss = s.contains("L");

Why you think you have to do this ? You just have to create a set and return it. Also, why are you manually adding 20 words ? For repetitive tasks, isn't it much better to use a loop ?

Collin M

Level 22 , Germiston, South Africa

30 September 2018, 18:58

solution

Remove line 28 and return s; Also, make sure you add 20 different words which starts with "L". In this case, you can use a loop which runs 20 times and adding "L" on each iteration plus one or more unique characters, or you can simply add each word manually but make sure that each word is different.

gery

Level 9 , Islamabad, Pakistan

30 September 2018, 23:54

keyword was: "different", while i added same value in reptiton.. here's code: public static Set<String> createSet() { //write your code here String[] a = { "La", "Lb", "Lc", "Lld", "Ll5", "Ll6", "Ll7", "Ll8", "Ll9", "Ll10", "Ll11", "Ll12", "Ll13", "Ll14", "Ll15", "Ll16", "Ll17", "Ll18", "Ll19", "Ll20" }; HashSet<String> s = new HashSet<String>(); //s.add for(String aa: a) { s.add(aa); } return s; }

Ankush Rajput

Level 25 , Bhopal, India

1 October 2018, 05:29

solution

There is a better way to initialize the set with values of array. You can do it in one line using Arrays.asList() function.

Set<String> s = new HashSet<>(Arrays.asList(a));

Bazsó Benjámin

Level 20 , Szombathely, Hungary

28 March 2019, 16:58

how do i make a loop that adds 20 different words starting with L?

Andrew

Level 29 , Seattle, United States

28 March 2019, 17:28

Create a string outside of a for loop. Create a for loop that runs 20 times. Inside the loop: - Concatenate the string so that it's unique (Hint: add something to the string each time so it's different). Remember to follow this pattern stringVariableName = stringVariableName + (the something you add each time). - Add the new string to the set. It might be a good idea to go back and review Strings and for loops since you will need a complete understanding of these moving forward. Something to keep in the back of your mind for later: when in a loop, it's best to use StringBuilder instead of concatenation. But that's a bit more advanced.