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Archiver (part 1)

Java Multithreading, Level 7, Lesson 15

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I tried different ways but one condition fails.

Let's write an archiver. At a minimum, an archiver should be able to zip and unzip files.

Let's start with the first one.
We need an archive manager. It will perform operations on the archive file (a file that will be stored on disk and have the zip extension). The class that will handle this will be called ZipFileManager. But the most important class will be called Archiver.
Programming and other fields have a concept called full (absolute) and relative paths. First off, let's wrap our heads around what a path is, in general. A path is a set of symbols that indicates where in the operating system a file or folder is located.
A full or absolute path is a path that starts with the root directory. In Windows, a disk is generally considered the root directory.
An example of a full path in Windows is: C:\user\zips\Test1.zip.
A relative path is a path relative to a directory. For example, zips\Test1.zip is the relative path of the file Test1.zip in relation to the C:\user directory (folder). The path relative to the C:\user\zips directory would just be Test1.zip, and would match the file name.
Note that, by default, both the full and relative path to a file include the name of the file.
1. Create a ZipFileManager class
2. Add a private Path zipFile variable to the class. We will use it to store the full path to the archive that we will be working with.
3. Add a ZipFileManager(Path zipFile) constructor. Initialize the class's zipFile field.
4. Declare a public createZip(Path source) throws Exception method with, for now, an empty implementation.
The Path source parameter is a path to something that we will zip.
5. Create an Archiver class and add a main method to it.
6. In the main method:
6.1 Ask the user to enter the full path to the archive from the keyboard. Don't forget that the file name is also part of the full path.
6.2 Create a ZipFileManager object, passing in the archive's file name. Figure out how to get a Path from a String.

Hint: look into the Paths class's get() method.

6.3 Ask the user to enter the path to the file to be zipped. Don't confuse this with the archive file, which we already entered. This time, we need the file that we'll compress, not the one we're going to store the compressed data in.
6.4 Call the ZipFileManager object's createZip method, passing the path to be zipped.

Requirements:

Create a ZipFileManager class.
A private Path zipFile field must be created inside the ZipFileManager class.
A constructor that initializes the zipFile field must be created inside the ZipFileManager class.
A public void createZip(Path source) throws Exception method must be created inside the ZipFileManager class.
Create an Archiver class and add a main method to it.

package com.codegym.task.task31.task3110; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.nio.file.Path; import java.nio.file.Paths; public class Archiver { public static void main (String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); System.out.println("Please enter the full path to the archive"); String enteredPath = reader.readLine(); Path path = Paths.get((enteredPath)); new ZipFileManager<>(path); System.out.println("Please Enter the path to the file to be zipped"); String fileToZip = reader.readLine(); Path path2 = Paths.get(fileToZip); ZipFileManager.createZip(path2); } }

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Norbert Backend Developer

17 November 2020, 15:47

In ZipFileManager class, try change createZip without static. it will be pass

Satya Vath

Level 31 , Vijayawada, India

20 March 2020, 10:09

Change line 15 to

ZipFileManager zipFileManager = new ZipFileManager(path);

Change line 19 to

zipFileManager.createZip(path2);

It will be verified