Couldn't pass this condition:
"The program should display the ordinal number of the number that is different from the others"
For me it looks good, part of my code:
if (numb1 == numb2 && numb1 != numb3)
System.out.println("3");
else if (numb1 == numb3 && numb1 != numb2)
System.out.println("2");
else if (numb2 == numb3 && numb3 != numb2)
System.out.println("1");package com.codegym.task.task04.task0424;
/*
Three numbers
*/
import java.io.*;
public class Solution {
public static void main(String[] args) throws Exception {
BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
String input1 = reader.readLine();
int numb1 = Integer.parseInt(input1);
String inputText2 = reader.readLine();
int numb2 = Integer.parseInt(inputText2);
String inputText3 = reader.readLine();
int numb3 = Integer.parseInt(inputText3);
if (numb1 == numb2 && numb1 != numb3)
System.out.println("3");
else if (numb1 == numb3 && numb1 != numb2)
System.out.println("2");
else if (numb2 == numb3 && numb3 != numb2)
System.out.println("1");
}
}