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package com.codegym.task.task04.task0413; /* Day of the week */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader br = new BufferedReader (new InputStreamReader(System.in)); String a = br.readLine(); int b = Integer.parseInt(a); if (b == 1) System.out.println("Monday"); if (b == 2) System.out.println("Tuesday"); if (b == 3) System.out.println("Wednesday"); if (b == 4) System.out.println("Thursday"); if (b == 5) System.out.println("Friday"); if (b == 6) System.out.println("Saturday"); if (b == 7) System.out.println("Sunday"); else System.out.println("No such day of the week"); } }

Use the keyboard to enter a number representing a day of the week. Then, depending on the entered number, display the name of the day of the week: "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday", if you enter a number greater than 7 or less than 1, display "No such day of the week".

Example for number 5:
Friday

Example for number 10:
No such day of the week

Requirements:

The program should read a number from the keyboard.
The program should display text on the screen.
If you enter a number from 1 to 7, you need to display the name of the day of the week.
If you enter a number outside the range of 1 to 7, then display a notification that there is no such day of the week.

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divya

Level 5 , hyderabad, India

23 November 2018, 11:17

if(day<=0 | day>7) System.out.println("No such day of the week"); Please try this it might help you

KryptoBlack

Level 7 , Mumbai, India

26 October 2018, 13:05

solution

if (b == 1)
System.out.println("Monday");
if (b == 2)
System.out.println("Tuesday");
if (b == 3)
System.out.println("Wednesday");
if (b == 4)
System.out.println("Thursday");
if (b == 5)
System.out.println("Friday");
if (b == 6)
System.out.println("Saturday");
if (b == 7)
System.out.println("Sunday");
else
System.out.println("No such day of the week");

The problem here is the else case here will always run except when the input b == 7. This is because the compiler thinks that the else case belongs to only the last if case. To avoid this you need to use nested if

if (condition) {
   ...
}
else {
   if (condition) {
      ...
   }
   else {
      ...
   }
}

In the above code, there is an if-else case and in the else case there is another if-else case. If the first condition is false it will go in else in which it will verify the second if condition and if that is also false it will go to the else and execute. To make it simple you can also write it like this,

if (condition) {
   ...
}
else if (condition) {
    ...
}
else {
   ...
}

You can use nested if-else how many times you want to just remember a single if statement has only one else...Sorry for the long post.

Hoist

Level 35 , San Diego, United States

25 January 2023, 05:03

Thanks Krypto --- nice post --- from 2018