整数类型转换练习

double m=12.0;
        byte num =(byte)(m/0); //Infinity强制转换为byte类型，结果为-1
        short s = (short) (m/0); //Infinity强制转换为short类型，结果为-1
        int i = (int) (m/0);//Infinity强制转换为int类型，结果为2147
        long l = (long) (m/0);//Infinity强制转换为long类型，结果为long的最大存储值
        float f = (float) (m/0);//Infinity强制转换为float类型，结果为Infinity
        double d = (double) (m/0); //Infinity强制转换为double类型，结果为Infinity
        char c = (char) (m/0);//Infinity强制转换为char类型，结果为?

        double j = 12;
        int i = (int)(j/0);
        System.out.println(i);