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Question about the task

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import java.io.*;

public class Solution {
    public static void main(String[] args) throws Exception {
        //write your code here
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));

        int num = Integer.parseInt(reader.readLine());
        int count = 0;
        if (num>0 && num<1000){
        while(num!=0){
        	num /=10;
        	count++;
                if (num%2==0 && count==1)
        		System.out.println("even single-digit number");

        	else if (num%2 == 1 && count==1)
        			System.out.println("odd single-digit number");


        	 if (num%2==0 && count==2)
        		System.out.println("even two-digit number");

             else if (num%2 == 1 && count==2)
        			System.out.println("odd two-digit number");


            if (num%2==0 && count==3){
        		System.out.println("even three-digit number");

        	else if (num%2 == 1 && count==3)
        			System.out.println("odd three-digit number");

Enter an integer from the keyboard in the range 1 - 999. Display a string description as follows:
"even single-digit number" - if the number is even and has one digit,
"odd single-digit number" - if the number is odd and has one digit,
"even two-digit number" - if the number is even and has two digits,
"odd two-digit number" - if the number is odd and has two digits,
"even three-digit number" - if the number is even and has three digits,
"odd three-digit number" - if the number is odd and has three digits.
If the entered number does not fall in the range 1 - 999, don't display anything.

Example for 100:
even three-digit number

Example for 51:
odd two-digit number

Requirements:

The program should read one number from the keyboard.
The program should use System.out.println() or System.out.print()..
If the number is even and has one digit, display "even single-digit number".
If the number is odd and has one digit, display "odd single-digit number".
If the number is even and has two digits, display "even two-digit number".
If the number is odd and has two digits, display "odd two-digit number".
If the number is even and has three digits, display "even three-digit number".
If the number is odd and has three digits, display "odd three-digit number".
If the entered number doesn't fall in the range 1 - 999, don't display anything
The program should display a string description of the number and nothing else.

package com.codegym.task.task04.task0427; /* Describing numbers */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int num = Integer.parseInt(reader.readLine()); int count = 0; if (num>0 && num<1000){ while(num!=0){ num /=10; count++; if (num%2==0 && count==1) System.out.println("even single-digit number"); else if (num%2 == 1 && count==1) System.out.println("odd single-digit number"); if (num%2==0 && count==2) System.out.println("even two-digit number"); else if (num%2 == 1 && count==2) System.out.println("odd two-digit number"); if (num%2==0 && count==3){ System.out.println("even three-digit number"); else if (num%2 == 1 && count==3) System.out.println("odd three-digit number"); } } } }

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Jurca Andreea-Luminita

Level 12 , Timisoara, Romania

30 January 2021, 13:04

U forgot a lot of { } after if and else.

package com.codegym.task.task04.task0427;

/*
Describing numbers

*/

import java.io.*;

public class Solution {
    public static void main(String[] args) throws Exception {
        //write your code here
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));

        int num = Integer.parseInt(reader.readLine());
        int count = 0;
        if (num>0 && num<1000){
        while(num!=0){
        	num /=10;
        	count++;

        	if (num%2==0 && count==1){
        		System.out.println("even single-digit number");}

        	else if (num%2 == 1 && count==1){
        			System.out.println("odd single-digit number");}


        	 if (num%2==0 && count==2){
        		System.out.println("even two-digit number");}

             else if (num%2 == 1 && count==2){
        			System.out.println("odd two-digit number");}


            if (num%2==0 && count==3){
        		System.out.println("even three-digit number");}

        	else if (num%2 == 1 && count==3){
        			System.out.println("odd three-digit number");
        }

        }
    }
}
}

Try like this.

Dinesh

Level 7 , Delhi, India

2 February 2021, 19:57

No proper output

Jurca Andreea-Luminita

Level 12 , Timisoara, Romania

3 February 2021, 01:24

try for even num%2 !=0