CodeGym/Help with Java Tasks/Calling a method whithin a method.

Level 9

Olympia

21.01.2019
1750views
14comments

Calling a method whithin a method.

Question about the task

Minimum of four numbers

Java Syntax, Level 2, Lesson 8

Resolved

I am missing something but stumped..

package com.codegym.task.task02.task0217;

/*
Minimum of four numbers

*/
public class Solution {
    public static int min(int a, int b, int c, int d) {
        //write your code here
        this.min(a,b);
    int answer1 = min(a,b);
    int answer2 = 0;
    if (c<=d)
    {
        answer2 = c;
    }
    else
    {
        answer2 = d;

    }
    if (answer1 <= answer2){
        return answer1;}

    else if {return answer2;}
    }

    public static int min(int a, int b) {
        //write your code here
int answer1=1;
if (a<=b){
    answer = a;}  //20
    else
    {answer = b;}
    return answer;
}

    }

    public static void main(String[] args) throws Exception {
        System.out.println(min(-20, -10));
        System.out.println(min(-20, -10, -30, -40));
        System.out.println(min(-20, -10, -30, 40));
        System.out.println(min(-40, -10, -30, 40));
    }
}

Comments (14)

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Fernando P Spitaliere

Level 6 , Atlanta, United States

1 February 2019, 06:19

Hi Bryce! For the sake of using a method within a method, have you thought what min(min(a,b), min(c, d)) would return? ;)

Tatoo Mindine

Level 4 , Douala, Cameroon

23 January 2019, 15:15

moreover actually this is how to call the method in another method in your public static int min(int a, int b, int c, int d) method ... you call the min(int a, int b) as a formula in the min(int a, int b, int c, int d) try this tip a = min(a, c); a = min(a, d); a = min(a, b); return a; just like the variable a above you can use b as well if you applied my previous tip for your min(int a, int b) method

Tatoo Mindine

Level 4 , Douala, Cameroon

23 January 2019, 15:05

you misusing {}... try this tip { int answer1; if (a < b) answer1 = a; else answer! = b; return answer1; }

Bryce Lindley

Level 9 , Olympia, United States

21 January 2019, 22:21

Thanks again for the help. I just installed NetBeans thru a recommendation from a book I am reading. But I will check out intelliJ!

Bryce Lindley

Level 9 , Olympia, United States

21 January 2019, 21:02

Thanks a ton. After cleaning up the code I also had to change line ten from this.min(a,b); to min(a,b); This was a difficult task.

Guadalupe Gagnon

Level 37 , Tampa, United States

21 January 2019, 21:44

I saw that and forgot to write it down, my bad. A couple syntax errors are to be expected, even high level programmers make these mistakes. A good IDE will help you a lot with those, like intelliJ. If it hasn't yet, the course will be instructing you to download that soon. You should be doing all your coding from that point forward in intelliJ, and after initial frustration of getting used to it, you will love the IDE.

Guadalupe Gagnon

Level 37 , Tampa, United States

21 January 2019, 20:37

useful

#1 You have an extra curly boy at line 38, remove this. #2 in your min(int,int) method you declare answer1 on line 30, but dont use it (you use answer). Change this to just answer. #3 in the min (int,int,int,int) method your last else if statement at line 25 should just be else. Remove the if. It looks like your code should work properly after this. I'm going to message you a cleaner solve.

Bryce Lindley

Level 9 , Olympia, United States

21 January 2019, 20:09

uber

Level 4 , Perth

23 January 2019, 20:05

You could have save typing by using the min method from the Math library and would have avoided the confusion. public static int min(int a, int b, int c, int d) { int newMinNumberAB; int newMinNumberCD; int newMinNumberAB = Math.min(a,b); // find first minimum int newMinNumberCD; = Math.min(c,d); // find second minimum // return the minimum of the last two minimum return Math.min(newMinNumberAB, newMinNumberCD); }

Guadalupe Gagnon

Level 37 , Tampa, United States

23 January 2019, 20:16

@uber You need to read the task requirements. The requirements specifically state: "The min(a, b, c, d) method must use the min(a, b) method.". Your code would not pass verification.

uber

Level 4 , Perth

23 January 2019, 20:38

My bad. some how i passed the task anyway. The correct solution: public class Solution { public static void main(String[] args) throws Exception { System.out.println(min(-20, -10)); System.out.println(min(-20, -10, -30, -40)); System.out.println(min(-20, -10, -30, 40)); System.out.println(min(-40, -10, -30, 40)); } public static int min(int a, int b, int c, int d) { int min1 = min(a,b); int min2 = min(c,d); return min(min1,min2); } public static int min(int a, int b) { a < b : a ? b; if (a < b) return a; else return b; } } or a more elegent way to implement Min(int a, int b) is to use: min = (a < b) ? a : b;

Guadalupe Gagnon

Level 37 , Tampa, United States

23 January 2019, 21:20

you could use the Math.min(a,b) in the min(a,b) method. This is my elegant way of solving (not the first way i solved it, back at level 3):

public static int min(int a, int b, int c, int d) {
   return min(min(a,b), min(c,d));
}

public static int min(int a, int b) {
   return Math.min(a,b);
}

Sebastian Eduard

Level 11 , Castell-Platja d'Aro, Spain

5 June 2019, 10:03

Wow!! What a level. One day I'll be able to think like that.

Guadalupe Gagnon

Level 37 , Tampa, United States

5 June 2019, 15:25

It gets easier the more experience that you get and the more you see examples like this.