Why secondMin showing the first int entered?

Question about the task

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Hey I'm a bit lost. I thought my code would do the following: If a new low encountered then set secondMin as min then set min to X the new low. In reality tho my secondMin only stores the first value entered. Any hints?

In this task, you need to:

Read integers from the keyboard until something else is entered, such as a string or a character.
At least two numbers must be entered. If less than two integers are entered, then terminate the program with an error. You don't need to handle this situation.
Display the second smallest integer entered from the keyboard. If several such numbers are entered, you must display any of them.
There may also be several minimum numbers.

Example input:

8

4 // Minimum number

7

4 // Minimum number

5 // Second smallest number

9

5 // Second smallest number

exit

Example output:
5

Requirements:

The program should read numbers from the keyboard.
The program should display a number on the screen.
The program should display the second smallest integer entered.
If several second smallest numbers are entered, then you need to display any one of them.
You need to read data from the keyboard in a while loop.

package en.codegym.task.pro.task04.task0410; import java.util.Scanner; /* Second smallest number entered */ public class Solution { public static void main(String[] args) { //write your code here int min = Integer.MAX_VALUE; int secondMin = Integer.MAX_VALUE; Scanner console = new Scanner(System.in); while (console.hasNextInt()) {int x= console.nextInt(); secondMin=min; if (x<min) { min=x; } } System.out.println(secondMin); } }

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hidden #11364598

Level 5

27 July 2023, 08:39

Thanks for the help good sir!

Thomas

Level 41 , Bayreuth, Germany

27 July 2023, 08:05

solution

Yep, it does exactly what you have coded and what you describe. 16: get the next int from the scanner and assign it to the variable x 17: without any condition (so in any way) assign current min to secondMin 18: check if x < min and if so assign x to min I don't know that task but that's what I'd do: inside a loop (aside from having a counter) 1. check if input < min yes -> assign min to secondMin input to min 2. else check if input < secondMin but not equal to min yes -> assign input to secondMin 3. outside the loop check if counter > 2 and display the result (OK, one could ask now if the counter counts any input or just inputs you keep. Eg. if you input 2 and 2, then you pretty much ignore the second input. For a good result I'd just count when you consider the input but I doubt Codegym thinks that way). Or you could try with a TreeSet and add all inputs to the set and then pick the second entry (if the size is > 1). set.pollFirst(); int result = set.pollFirst(); but that of course needs more memory. And if the counter requirements means to count all inputs you need a dedicated counter instead of checking the sets size (but then an input like 2 2 would give an output of 2 null)