Please Help out . What am i doing wrong, I cant satisfy the last req?

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package com.codegym.task.task04.task0427; /* Describing numbers */ import java.util.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here Scanner input = new Scanner(System.in); int n = input.nextInt(); /* "even single-digit number" - if the number is even and has one digit, "odd single-digit number" - if the number is odd and has one digit, "even two-digit number" - if the number is even and has two digits, "odd two-digit number" - if the number is odd and has two digits, "even three-digit number" - if the number is even and has three digits, "odd three-digit number" - if the number is odd and has three digits. If the entered number does not fall in the range 1 - 999, don't display anything. */ String e1n = "even single-digit number"; String o1n = "odd single-digit number"; String e2n = "even two-digit number"; String o2n = "odd two-digit number"; String e3n = "even three-digit number"; String o3n = "odd three-digit number"; if ((n<10) && (n%2 == 0)) System.out.println(e1n); else if ((n<10) && (n%2 != 0)) System.out.println(o1n); else if ((n < 100) && (n%2 == 0)) System.out.println(e2n); else if ((n< 100) && (n%2 != 0)) System.out.println(o2n); else if ((n <= 999) && (n%2 == 0)) System.out.println(e3n); else if ((n <= 999) && (n%2 != 0)) System.out.println(o3n); } }

Enter an integer from the keyboard in the range 1 - 999. Display a string description as follows:
"even single-digit number" - if the number is even and has one digit,
"odd single-digit number" - if the number is odd and has one digit,
"even two-digit number" - if the number is even and has two digits,
"odd two-digit number" - if the number is odd and has two digits,
"even three-digit number" - if the number is even and has three digits,
"odd three-digit number" - if the number is odd and has three digits.
If the entered number does not fall in the range 1 - 999, don't display anything.

Example for 100:
even three-digit number

Example for 51:
odd two-digit number

Requirements:

The program should read one number from the keyboard.
The program should use System.out.println() or System.out.print()..
If the number is even and has one digit, display "even single-digit number".
If the number is odd and has one digit, display "odd single-digit number".
If the number is even and has two digits, display "even two-digit number".
If the number is odd and has two digits, display "odd two-digit number".
If the number is even and has three digits, display "even three-digit number".
If the number is odd and has three digits, display "odd three-digit number".
If the entered number doesn't fall in the range 1 - 999, don't display anything
The program should display a string description of the number and nothing else.

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Level 4

Expert

15 February 2023, 16:34

My way, correcting your negative mode: import java.io.*; public class Solution { public static void main(String[] args) throws Exception { BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(reader.readLine()); if ((a > 0) && (a < 10) && (a % 2 == 0)) { System.out.println("even single-digit number"); } else if ((a > 0) && (a < 10) && (a % 2 != 0)) { System.out.println("odd single-digit number"); } else if ((a > 0) && (a > 9) && (a < 100) && (a % 2 == 0)) { System.out.println("even two-digit number"); } else if ((a > 0) && (a > 9) && (a < 100) && (a % 2 != 0)) { System.out.println("odd two-digit number"); } else if ((a > 0) && (a > 99) && (a < 1000) && (a % 2 == 0)) { System.out.println("even three-digit number"); } else if ((a > 0) && (a > 99) && (a < 1000) && (a % 2 != 0)) { System.out.println("odd three-digit number"); } } } 👍👍

IVAN

Level 17 , Milan, Italy

7 November 2019, 20:00

I did the task in a totally different way: package com.codegym.task.task04.task0427; /* Describing numbers */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); int a = Integer.parseInt(reader.readLine()); boolean start; if(a>=1&&a<=999) start=true; else start=false; if(start){ String numString = String.valueOf(a).toString(); char[] charString = numString.toCharArray(); int digit = charString.length; String stringDigit = ""; if(digit==1) { stringDigit = "single"; }else if(digit==2) { stringDigit = "two"; }else if(digit==3) { stringDigit = "three"; } if(a%2==0){ System.out.println("even " + stringDigit + "-digit number"); }else{ System.out.println("odd " + stringDigit + "-digit number"); } } } }

CodeIt

Level 11

28 May 2019, 09:50

Set condition for numbers not in range 1 - 999.

suraj tiwari

Level 16 , Delhi, India

28 May 2019, 08:50

try this package com.codegym.task.task04.task0427; /* Describing numbers */ import java.io.*; public class Solution { public static void main(String[] args) throws Exception { //write your code here BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in)); int n = Integer.parseInt(bufferedReader.readLine()); if(n%2 == 0){ if(n>=1 && n<=9) System.out.println("even single-digit number"); else if(n>=10 && n<=99) System.out.println("even two-digit number"); else if(n>=100 && n<=999) System.out.println("even three-digit number"); } else{ if(n>=1 && n<=9) System.out.println("odd single-digit number"); else if(n>=10 && n<=99) System.out.println("odd two-digit number"); else if(n>=100 && n<=999) System.out.println("odd three-digit number"); } } }

Guadalupe Gagnon

Level 37 , Tampa, United States

27 May 2019, 02:52

your code has outputs when the number is less than 1.