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Question about the task

Sum of the digits of a three-digit number

Java Syntax, Level 3, Lesson 12

Under discussion

Write the code for sumDigitsInNumber(int number). The method takes a three-digit whole number. You need to calculate the sum of the digits of this number, and then return the result.

Consider this example:
The sumDigitsInNumber method is called with the argument 546.

Example output:
15

Requirements:

The program must not read data from the keyboard.
The sumDigitsInNumber(int) method must be public and static.
The sumDigitsInNumber method must return an int.
The sumDigitsInNumber method should not display anything.
The sumDigitsInNumber method must return the sum of all digits in the parameter number.

package com.codegym.task.task01.task0132; /* Sum of the digits of a three-digit number */ public class Solution { public static void main(String[] args) { System.out.println(sumDigitsInNumber(546)); } public static int sumDigitsInNumber(int number) { //write your code here int n = 546 ; int sum = 0; while (n > 0) { sum =sum + n % 10; n = n /10; } return sum; } }

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YO MA

Level 5 , Mumbai, India

8 November 2019, 06:55

you can rather try this int result = number/100 + ((number-99)/100) + ((number+99)/100); //5.46+4.47+6.45 return result;

poosa sudeshna

Level 5 , Hyderabad, India

6 November 2019, 03:34

In your code, you didn't used the value of the variable that passed as a parameter in the method. Instead you have used hard coded value. So remove the line10. And replace variable 'n' with 'number'. It should work.

Guadalupe Gagnon

Level 37 , Tampa, United States

5 November 2019, 18:31

The problem is that you hard coded "546" into your method. If you changed line 10 to pass in 657 to the method, it should output 18, but because it is hard coded it would still output 15. The method should accept any (three digit) number and return the sum of its digits.